Logic Masters Deutschland e.V.

Erica 16

(Eingestellt am 26. November 2025, 18:15 Uhr von SennyK)

Erica 16

Today we have rather challenging Erica with tricky things to notice ;-)
Time flies very quickly, so make sure you use it to your advantage! :-)
I hope you will enjoy and I would be really grateful for all the comments and ratings.

Normal sudoku rules apply.

German whisper: Neighbouring/adjacent digits along a green line have a difference of at least 5.

X/V: Digits in cells joined by an X sum to 10. Digits in cells joined by a V sum to 5. Not all Xs and Vs are given.

Entropic: Any sequence of 3 adjacent digits along a peach line must have a low digit (123), a medium digit (456) and a high digit (789). For lines shorter than 3 cells, each digit must belong to a different entropic group.

SudokuPad Link

Entropic Line Explanation:

Basically, if one digit on the line is low, then every third digit will also be low; same applies for the remaining groups.

The Erica Series:
Episodes: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15

If you liked this puzzle, I recommend trying out my other puzzles:
Symmetrical Fan
Night Club
Cops & Robbers
Broken Flashlight in the Dark
Blown Fuses in Electrical Installation
Important Hour on the Clock
Let Me Introduce Myself
Positive Symmetry
Pretty Odd Shaded Area <- Recommended for you!
It's What You Do in the Dark That Puts You in the Light
What Was the Sum Again?
(+5)-Yang <- Recommended for you!
Disgroup Joints
Find It All
What the Fog?
10-Arrows
Negative 8 YY <- Recommended for you!
Why-Why? <- Recommended for you!
French Wrench

Lösungscode: Fifth (5th) column of the grid from top to bottom.

Zuletzt geändert am 26. November 2025, 21:48 Uhr

Gelöst von jalebc, keenbowl, noodlehead, HeyItsErin, Adrian71, BBoris, Iluvsodah, ketchup_monster, cryptique, OhHeyGuysItsMax, Fizz, Killer-Ly , gxorgx, sparkymanu, wuc, brimmy, jgarber, anthe95, SKORP17, ... TaeChi, kolb_elias, NineK, cegie, schnitzl, xiaozhu, JustDoggy, Ste1729, Roseelms, Crul, galium_odoratum, 11srube, Rearden, Deivi55, Photyne, Dean, kross, Uhu, adam001, u_kodus, akin1012, Barrels
Komplette Liste

Kommentare

am 26. November 2025, 22:08 Uhr von wuc
Cool 2* puzzle with nice constraint interactions thx.

am 26. November 2025, 22:01 Uhr von sparkymanu
Fun Erica puzzle as always, thank you for that !
As for the difficulty, I would say 1 or 2*

Zuletzt geändert am 26. November 2025, 22:01 Uhr

am 26. November 2025, 21:52 Uhr von Ashen
I had two solutions that did not violate the rules. When I got to the end of the puzzle I was left with c3r4-6 and c7r4-6. I shaded the entire puzzle via entropic groups to make sure. Perhaps I missed something but the two cell entropic lines were the hitch for me. I understood they had to be from different groups but could not logically deduce which groups at the end. I got there via a logic leap though. Overall I really enjoyed this one. Great Work!!!

SK: Thank you for the comment! For me those cells resolved pretty early on (keeping in mind that digits in 2-cell entropic lines musty be from different entropic groups). You can reach me on DC (SennyK7), I will share replay of my solve :-)

am 26. November 2025, 21:44 Uhr von SennyK
Clarified entropic line rule

am 26. November 2025, 21:38 Uhr von ketchup_monster
I agree that it's intuitive to have 2 different groups, but it's technically not needed. Having 2 of the same does not violate the Entropic rule as given here.

Zuletzt geändert am 26. November 2025, 20:57 Uhr

am 26. November 2025, 20:46 Uhr von ketchup_monster
Super fun as always! Just wanted to point out a small technicality: The entropic line only has a rule for 3 adjacent digits and because of that there is an ambiguity in the entropic lines of size 2. A different interpretation gave me a different solution (with the same column 5 though, so still works!)

SK: Thank you for comment! I thought that it is obvious that 2 cell entropic line will have each digit from a different group, so 2 of 3 groups will be used, what is the other possibility?

Schwierigkeit:2
Bewertung:94 %
Gelöst:93 mal
Beobachtet:0 mal
ID:000QB7

Variantenkombination Online-Solving-Tool

Lösung abgeben

Lösungscode:

Anmelden