The rabbit and the little ninja
(Eingestellt am 23. August 2023, 22:52 Uhr von filuta)
Have fun!
Rules of the puzzle:
Slitherlink rules: Draw a loop along the edges such that every number indicates how many neighboured edges are visited by the loop.
In this puzzle, however, you are solving two slitherlinks - yours and your partner's. Each of you has their own set of clues.
For your slitherlink: all your clues in its inside and all partner's clues outside of it must be valid.
For your partner's slitherlink: all your clues outside of it and all partner's clues in its inside must be valid.
Moreover, if the two slitherlinks share an edge between two cells, then its orientation (outside/inside) must be the same in both grids.
You should only to tell your partner:
(1) the nature (outside/inside) of any cell you deduce,
(2) the value of a clue (from your set) that is in a cell which was deduced to be outside their slitherlink.
Examples:
Player 1 clues:
- 3 in r1c2 is outside player 1 loop so it doesn't have to be valid here (but can be) and it is also outside player 2 loop, so it has to be valid there,
- 1 in r2c1 is outside player 1 loop so it doesn't have to be valid here (but can be - and in fact is valid) and it is inside player 2 loop, so it doesn't have to be valid there either (but can be - and in fact is),
- 2 in r2c2 is inside player 1 loop so it has to be valid here, it is also inside player 2 loop, so it doesn't have to be valid there (but can be),
- 1 in r2c4 is inside player 1 loop so it has to be valid here and it is also outside player 2 loop, so it has to be valid there as well.
Player 2 clues:
- 1 in r3c1 must be valid in both grids (outside loop 1, inside loop 2),
- 1 in r3c2 must be valid only for loop 2 (inside both loops)
- 0 in r3c4 doesn't have to be valid in either loop (inside loop 1, outside loop 2)
- 1 in r4c2 must be valid only for loop 1 (outside both loops).
The edges rule:
there are four edges (between two cells) that are part of both loops, the three blue ones satisfy the rule about the edges, but the red one doesn't (has the left cell outside loop 1, but inside loop 2).
If you want to solve on paper, you can find the grids here:
player 1
player 2
If you want to solve on-line, you can find penpa+ links here (answer check on edges in both grids):
player 1
player 2
In either case, you are given three grids - the leftmost one contains your set of clues, the middle one is to draw your loop and the right one to draw your partner's loop.
Lösungscode: For all cells in rows 5 and 6 (from left to right) write "I" if the cell is inside the loop and "O" if it is outside the loop - first for player 1 loop, then for player 2 loop.
Kommentare
am 1. November 2023, 00:42 Uhr von Aaronomys
I solved this puzzle as player 2 with Piatato as my partner, and I can say that we had great fun!
It was funny at the start when we both struggled to understand the implications of the ruleset, but once we did we had a relatively smooth solve. Personally, my favorite moment was the logic in r4c3.
Thank you for setting yet another great puzzle!
am 1. November 2023, 00:41 Uhr von Piatato
Loads of fun! Great interactions throughout, both logically and socially! Big version please! :D
am 25. August 2023, 22:33 Uhr von jessica6
The hardest thing was to understand the rules correctly, they still can be confusing:
A clue from my partner's grid is valid in MY grid if it is outside MY slitherlink (not outside my partner's).
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haha, yeah, formulating the rules was also the hardest thing when making the puzzle. thanks for trying it out.
am 24. August 2023, 07:31 Uhr von Kafkapharnaum
Once again, what an amazingly creative and fun puzzle! And I imagine that the experience must be even better as a 'proper' solve, as for me, well, I kinda just played it on my own, and so in doing so I kinda broke the 'can/can't tell' rule XD
But it was really fun reconciling the two grids, and also a fair bit tricky, what with the 'edges orientation' rule too. An exceptional creation once again!
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Thank you so much, although at least this time all points for creativity go to my predecessors.
am 24. August 2023, 07:22 Uhr von filuta
fixed solution code
am 24. August 2023, 06:33 Uhr von Kafkapharnaum
(To get the answer check to popup, one has to very specifically use the green-colored edges)
am 24. August 2023, 06:23 Uhr von jessica6
So, to clarify, the example solution isn't valid because the red edge violates the edge rule?
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correct, also I should emphasize, the example is not indended to be a valid puzzle, just a diagram to illustrate the rules
