Pentominous 2

(Eingestellt am 16. September 2026, 16:24 Uhr von Lizzy01)

Rules:
Divide the grid into pentominoes (groups of 5 orthogonally connected cells) such that no two orthogonally touching pentominoes are the same shape (rotations and reflections count as the same shape)

Try it here.

If you like this puzzle, you might also like to try these:
polyominous
pentominous

Lösungscode: For each of the last 4 rows, the number of different shapes of pentomino present in that row (i.e if there are multiple of the same shape of pentomino you only count one of them) (4 digits)

Gelöst von gepa, puzzler05, Christounet, Adaki, mathpesto, JustinTucker, dogfarts, Calesch, misko, saskia-daniela, marcmees, CHalb, Jesper, Shmartus, Phistomefel, KNT, MaizeGator, hurrdurr, pms_headache, WhiteWarat, Kpn, cowabunghole, Thanos13, VesperV, amirs, Khatru, Piatato, kangaroo, webato, jessica6, moss, EvanB, yayitsHannaH, gorilla, ildiko

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