Polyominous
(Eingestellt am 6. August 2026, 12:08 Uhr von Lizzy01)
This is a new rule I came up with, I'd love to know what you think of it.
I estimate the difficulty of this puzzle at about 2.5 stars, since it has a bit of a sting in the tail. (No bifurcation needed!)
If you'd like to try a harder puzzle combining polyominous with sudoku, click here.
Rules:
Polyominous
Divide the grid into polyominoes (i.e. orthogonally connected groups of 2 or more cells).
Some borders between polyominoes have been given.
No polyomino can contain a collection of cells within it that is the exact same shape as the full shape of an orthogonally neighbouring polyomino (rotations/reflections count as the same shape).
(E.g. if one 4-cell polyomino is just a fully horizontal line of cells, then any polyomino touching it orthogonally cannot be or contain a horizontal or vertical line of 4 adjacent cells.)
Lösungscode: for each cell in column 4, the size of the polyomino it belongs to. (7 digits)
Kommentare
am 11. August 2026, 22:34 Uhr von Piatato
Fun puzzle, thanks!
--Thank you!
am 11. August 2026, 21:43 Uhr von alanb
Is there an upper limit on the size of the polyominoes? If you can make them arbitrarily large, I don’t see how there could be a unique solution.
--There is no particular given limit, but you can't take the cells on both sides of a border with the same polyomino, which in some places limits the maximum sizes you can fit in, or making one large polyomino would force a different polyomino to become very small, etc. The solution is unique, as far as I know.
— Thanks! I get it now. Reading comprehension issue on my part. I can see the rules are clear :)
am 6. August 2026, 19:06 Uhr von Franjo
Much easier than expected. Thank you very much for creating and sharing this lovely little puzzle.
--Thanks!
am 6. August 2026, 17:31 Uhr von marcmees
Fun rule with potential. Beginning went smooth, the finishing pieces needed some puzzling. Thanks
--Thank you!
