Distillation
(Eingestellt am 3. Februar 2026, 09:44 Uhr von juggler)
click on the puzzle image to play
- In each N-by-N Latin Square, place the digits 1 to N once each in every row and column.
- Digits on an arrow sum to the digit in the attached white circle.
- Each grey circle has an odd sum.
See also
Lösungscode: Row 1
Zuletzt geändert am 6. Februar 2026, 10:28 Uhr
Gelöst von Crusader175, Default, zeniko, oskode, tuturitu, Krisonium, gdc, Blake Saligia, vrcngtrx_, fkib, MSDOS, dandydaniel, SKORP17, Exigus, cornish-john, ratolibre, 26rfeng, NEWS, dorverbin, SZCrow, LenD, Atticus837, Stobart, Neumino
Kommentare
am 6. Februar 2026, 01:44 Uhr von Atticus837
Great puzzle!
You may want to adjust the rules to specify each *grey* circle has an odd sum for clarity, although I don't think it's a huge issue.
am 3. Februar 2026, 09:50 Uhr von Crusader175
What a cool puzzle!
