Inset
(Eingestellt am 7. Dezember 2024, 08:47 Uhr von juggler)
In each N-by-N Latin Square, place the digits 1 to N once each in every row and column.
Each circle has an odd sum. Each square has an even sum.
Lösungscode: Row 4 (8 digits)
Kommentare
am 17. Januar 2025, 15:29 Uhr von ThymePass
Great puzzle and I hope there are more of these to come!
am 3. Januar 2025, 15:17 Uhr von Nurator
That was fantastic! It was really fun to go up and down between the different grids :)
am 2. Januar 2025, 20:33 Uhr von vitaminz
Loved this! The parity interaction with the digit restrictions from adjacent boxes was masterfully crafted
am 29. Dezember 2024, 13:13 Uhr von chameleon
Interesting deductions :)
Don't know how it ended up estimated as 2* for difficulty, though
am 12. Dezember 2024, 23:58 Uhr von wuc
Wow hat to Switch to tablet. Awesome fun. Harder than 2 Stars for me.
am 12. Dezember 2024, 03:34 Uhr von MattYDdraig
Love the concepts in this and it makes a great puzzle.
am 8. Dezember 2024, 17:09 Uhr von skuntsel
Amazing puzzle as usual with a few Eureka moments and reiterations of your logics back and forth. Highly recommended!
am 7. Dezember 2024, 23:01 Uhr von Myxo
Lovely!
am 7. Dezember 2024, 19:10 Uhr von egubachu
Sublime! It got even better than the version I tested! Well done!
am 7. Dezember 2024, 13:52 Uhr von Franjo
I love how the solving path steps downstairs and then up again. Thank you very much for creating and sharing another novelty.
am 7. Dezember 2024, 09:29 Uhr von SamuPiano
Super cool one! Thanks for the puzzle!
