London Bridges
(Eingestellt am 30. August 2026, 22:00 Uhr von XeonRisq)
- Normal sudoku rules apply.
- Bridge Shading : Divide the digits into three sets, Set 1 {A, B, C, D} ;
Set 2 {E, F, G, H} ; Bridge cells {X}
Set 1 and Set 2 will be shaded as different colors. Bridge cells will act as both shaded colors.
- Digits in the top corner of cells denote the size of the orthogonally connected cells of the same shading BEFORE crossing any bridge cells. The cell with the number will always be the left most cell in the top row of the shaded area. (? = a single digit sum)
- Shade Sum Circles : Circles in a shaded area NOT including or crossing bridge cells, will sum to the number of cells in that area. If a circle exists in a bridge cell, the counting properties of the cell no longer apply.
- SudokuPad link - link to solve puzzle below
Shade the grid such that all cells of the same color are connected with the assistance of bridge cells.
Below is an example of how the shading works from an empty section of grid to a possible shading solution :
(Lines demonstrate connectivity through bridge cells)
Lösungscode: Row 2 followed by Column 9
Kommentare
am 2. September 2026, 18:25 Uhr von Chilly
Really enjoyed that one - the whole solve path was really nice, and nowhere near as hard as I thought it would be, once you get started.
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Appreciate the feedback. I did try to make this one a bit more approachable given the twist on the shading constraint.
am 31. August 2026, 23:30 Uhr von bansalsaab
That was fun ruleset Made it harder. Kept making same mistake of putting a specific digit in R3C5 and breaking the set.
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Really glad your experience was enjoyable. And that is a peculiar cell in this puzzle, but I'll leave the specifics to the future solvers ;) Appreciate the solve and feedback.
am 31. August 2026, 20:17 Uhr von sanabas
Another fun one. Not as tough as it first appears.
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Thanks for the solve/feedback. I really tried to make it both interesting and a bit easier than my normal puzzle; hope people give this one a spin, I really think it's an interesting idea.
am 31. August 2026, 17:33 Uhr von PierreTombal
I fear I am not understanding the rules at all. Surely you cannot place an 11 or 14 in a circle?
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All circles in the same shading region will sum together to add to the 11 or 14 you speak of. So if there were 3 circles in that shading region, 4+4+6 could satisfy the 14, while 2+4+5 could satisfy the 11.
Let me know if this is still confusing.
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Right... Got it.
