Logic Masters Deutschland e.V.

Quantum Cryptography

(Published on 9. August 2026, 12:47 by Tobias Brixner)

Puzzle link: Play on SudokuPad.

Short rules:

Normal Sudoku rules apply. The sum of the digits in A_j and B_j, where A_j ≥ B_j, j = 1,...,14, must occur in a cell at the shortest possible Manhattan distance from both A_j and B_j.

Long rules:

Normal Sudoku rules apply. In each cage labeled A_j, where j = 1,...,14, there is a person called Alice_j, who wants to exchange a “quantum key” with a person called Bob_j, who is located in a cage labeled B_j with the same j. For this purpose, a pair of “entangled photons” is created by “spontaneous parametric down-conversion” of a “pump photon” in a cell that contains the frequency of the pump photon, P_j, as a digit. That cell must be located at the shortest possible Manhattan distance from both A_j and B_j, with both distances being equal. The Manhattan distance between two cells is the sum of their vertical and their horizontal separations measured in numbers of cells.

One of the created entangled photons is the “signal” with frequency A_j that is sent to Alice_j and written as a digit in cage A_j, and the other is the “idler” with frequency B_j sent to Bob_j and written as a digit in cage B_j. Due to the conservation of energy, P_j = A_j + B_j, and in addition by convention A_j ≥ B_j for all j.

Your feedback, ratings and comments are highly appreciated. Have fun!

Background: The process of spontaneous parametric down-conversion can indeed be used to create pairs of entangled photons, with energies as stated in the puzzles rules, that in turn are used for quantum key distribution in cryptography.

Example: The following image provides a fully solved example on a 4x4 grid. You may solve the example for yourself here on SudokuPad.

Solution code: All digits of row 8 (from left to right) without spaces.

Last changed on on 31. August 2026, 17:13

Solved by Simon Yuan, SS20x3, psams, SKORP17, pmays123, lalara, kangaroo
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Comments

on 31. August 2026, 17:13 by Tobias Brixner
Added relevant tags

Last changed on 9. August 2026, 23:08

on 9. August 2026, 23:06 by pmays123
Fun and well executed puzzle. Thank you for sharing!
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Many thanks for your comment! - TB

Last changed on 9. August 2026, 19:59

on 9. August 2026, 18:33 by psams
Nice puzzle. Takes an investment in marking up the puzzle to get the first digits, then gets a bit easier.
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Thank you so much for playing and commenting. Concerning the "initial investment", this probably depends on the solve path; it is possible to get the first digit without any markup, and for the next digits it is also usually sufficient to concentrate just on ~3 cells at a time. Glad you liked it anyway! - TB

Last changed on 9. August 2026, 15:08

on 9. August 2026, 14:27 by RockyRoer
So, I made a puzzle with similar rules (https://logic-masters.de/Raetselportal/Raetsel/zeigen.php?id=000U7Y) and I'm trying to understand the differences. In your puzzle, A's are always greater than or equal to Bs... and the location of the sum is always in one of the center cells between them, correct?
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Hadn't known your puzzle, thanks for pointing it out. Indeed, you summarized the difference between the two rule sets correctly. - TB

Difficulty:3
Rating:N/A
Solved:7 times
Observed:2 times
ID:000U94

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