Shade some cells and divide the cells into regions.
Divide the grid into orthogonally connected regions.
Enter the size of each region into all cells belonging to that region.
Regions of the same size may not share an edge.
Shade cells so that all shaded cells form a single orthogonally connected area and all unshaded cells form a single orthogonally connected area.
No 2×2 block may be entirely shaded or entirely unshaded.
The puzzle consists of two grids representing two layers of the same board, one placed directly above the other.
Cells in corresponding positions of the two layers are considered orthogonally adjacent.
The Fillomino and Yin-Yang rules apply in three dimensions:
A Fillomino region may extend across both layers using orthogonal connections between corresponding cells.
Shaded and unshaded regions are considered connected in the full three-dimensional structure; they do not need to be connected within each individual layer.
The 2×2 restriction applies to every 2×2×1 slab in the three-dimensional structure, regardless of orientation.
Every Fillomino region must be either entirely shaded or entirely unshaded.
No two Fillomino regions belonging to the same Yin-Yang region may have the same size.
Online Tool Link: Penpa+
Lösungscode: Row 1 followed by Row 5 (Left to right, considering both grids next to each other, ie Row 1 contains 12 numbers)
am 20. Juni 2026, 23:42 Uhr von yttrio
This had some fantastic opening logic, and the solve continued nicely all the way to the finish.