Logic Masters Deutschland e.V.

Quiet Room

(Eingestellt am 16. Juni 2026, 13:03 Uhr von marty_sears)

    Rules:

    Normal sudoku rules apply.

    Along a line that occupies N cells, every pair of adjacent digits must have a difference of at least N.

    If a black dot sits between two digits, one is double the other.

Lösungscode: Column 2 reading downwards

Zuletzt geändert am 16. Juni 2026, 18:06 Uhr

Gelöst von Blake Saligia, saiifh, Dr Logic, jalebc, HighEagle, Enchanter73, Joyofrandomness, phono, BlackRaven, efnenu, Alce, lars, ezruhh, pmays123, Leaving Leaves, EmX68, careBear, Miatc, PinkNickels, Dibi, ... Sudokujoker, PropitiousTortoise, jimmyjames, stranac, Boroh, Pairot, NabnerFFD, Siempie, amylou7099, kdwji, uninsured, werkelmann, janinamarie, deangaudet, cascadeshiker, hermitko, urmaul, Slayer
Komplette Liste

Kommentare

am 25. Juni 2026, 17:20 Uhr von ThymePass
This was a fun ruleset. Cheers!

am 25. Juni 2026, 16:12 Uhr von davidz32z
Two star puzzle with a three star finish! Very very nice ruleset

am 19. Juni 2026, 18:27 Uhr von MikeMeech
Nice one!

am 17. Juni 2026, 23:49 Uhr von Snaques
Shhhhh ;)

Loved the puzzle and the puzzle name. It was a new ruleset for me, but at the same time felt all so familiar.

am 17. Juni 2026, 12:50 Uhr von mscha
Cute little puzzle with a tricky endgame

am 17. Juni 2026, 10:44 Uhr von GeorgeTheToad2
Very nice

am 17. Juni 2026, 03:20 Uhr von Crusader175
Fun puzzle!

am 16. Juni 2026, 20:41 Uhr von blackjackfitz
Huzzah!

am 16. Juni 2026, 17:45 Uhr von Franjo
Thank you very much for creating and sharing another beautiful puzzle. The short line made me smile at last …

am 16. Juni 2026, 16:00 Uhr von gren
As per usual with your puzzles, the last disambiguation is always the best one :)

am 16. Juni 2026, 15:15 Uhr von pmays123
Very nice. Thanks! :)

am 16. Juni 2026, 14:20 Uhr von BlackRaven
Very good and smooth puzzle

am 16. Juni 2026, 13:37 Uhr von Dr Logic
interesting puzzle! I enjoyed :)

Schwierigkeit:2
Bewertung:94 %
Gelöst:412 mal
Beobachtet:1 mal
ID:000TBF

Lösung abgeben

Lösungscode:

Anmelden