Logic Masters Deutschland e.V.

Schrödinger's Carry-on

(Eingestellt am 1. April 2026, 02:16 Uhr von jwsinclair)


Fill each row, column, and box with the digits 0-6 once each. Exactly one cell in each row, column, and box is a "Schrödinger's cell," which contains two digits. Two Schrödinger's cells cannot contain the same pair of digits.

A cell's value is equal to the sum of its digits. For solution check purposes, if a cell's value is from 0-9, enter the *digit* equal to its value; otherwise, the cell may be left empty.

Indexing: Cells with red squares are index cells. If an index cell in column X has a value of Y, then the cell in column Y in the same row has a value of X (e.g. if r3c1 has a value of 5, then r3c5 has a value of 1). An index cell may contain two digits, but may not have a value greater than 6. If an index cell has a value of zero, the value being indexed does not appear in the row. Nothing in these rules prevents a value from repeating in a row, even if one instance of that value is referenced by an index cell.

Arrows: The sum of the values along an arrow is equal to the value in the connected circle.

Note: because of hard-to-explain issues related to the ruleset, in-progress solution-checking doesn't work properly in this puzzle. You'll just have to trust yourself. The "puzzle solved" message will still trigger when you have the correct solution.

SudokuPad

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Lösungscode: Will be provided in the puzzle's completion message


Gelöst von arctan, dumediat, tallcat, jmw, Crusader175, sorryimLate, Andrewsarchus, WvdWest, Sotehr, PippoForte, Nell Gwyn, SKORP17, widjo, mercierus, spoonfed, Chopper5, SudokuFan, Neumino, mew_rocks, Dcs, jkuo7
Komplette Liste

Kommentare

am 1. April 2026, 07:04 Uhr von Crusader175
What a brilliant puzzle!

am 1. April 2026, 04:32 Uhr von tallcat
Bonkers in all the right ways!

am 1. April 2026, 03:02 Uhr von dumediat
Surely this puzzle cannot be both brilliant and hilarious...oh wait, it can!

Schwierigkeit:3
Bewertung:91 %
Gelöst:21 mal
Beobachtet:1 mal
ID:000S45

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Lösungscode:

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