Parity lighthouse
(Eingestellt am 29. März 2026, 23:55 Uhr von Killer Joe)
Hello.
I created this puzzle before I came up with the modular islands and entropic islands (which I will post soon).
I expected it to be quite easy, but the feedback was mixed.
There were only a few testers, but they agreed that the first step is the hardest, even though they could fairly easily bifurcate the options in their head without pencil marks.
Normal Sudoku rules apply.
A digit placed in a circle indicates how many digits of the same parity (odd or even) it can see horizontally and vertically, including itself.
Digits of the opposite parity block vision.
Have fun.
Lösungscode: Row 9, first 6 digits.
Kommentare
am 12. August 2026, 14:46 Uhr von bboom
I love the simplicity of the rule-set. The break-in is definitely the tricky part, and I'll admit I did not fully prove the solution was unique.
I got to a point where I was fairly certain a certain digit could only go in one place in box 1, but I got a bit stuck trying to absolutely prove it and instead just went with it to see if I would get stuck somewhere.
Maybe there was a simple proof I overlooked, but otherwise I can see how a solver who doesn't like to go with gut feeling at times would get a bit frustrated.
am 31. März 2026, 22:08 Uhr von Sinuit
Thanks for this great puzzle. I‘m also puzzled by the rating, because I found it very enjoyable. Yes, the break-in was the hardest part, but at least it is quite clear where to start. :-)
am 31. März 2026, 14:44 Uhr von Snookerfan
Great puzzle! The break-in is interesting and tricky, but still not that hard to find. Much higher rating deserved in my opinion. Thanks
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Thank you for your comment. They can't all be winners. Although personally I'm very happy with this puzzle. Thanks for checking it out anyway! Grts Jonesy.
am 30. März 2026, 21:41 Uhr von balpha
This definitely deserves better than the 77% it currently sits at, I really enjoyed it. Thanks for sharing!
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Thanks for your comment. I wonder if placing a simple kropki dot would have been a good idea to give the solver an anchor to go off. Grts Jonesy.
