Digit Counters with a Side of Parity
(Published today, 00:00 by FIT7Y)
Rules:
Place the digits 1-9 once each into every row, column, and box.
Digits in a circle count how many digits in the (up to 9) cells from the surrounding 3x3 centered on that circle have the same (even/odd) parity as the digit in that circle.
Digits in a square count the number of unique digits in the (up to 9) cells from the surrounding 3x3 centered on that square.
Have fun solving!
Solution code: Column 1 from top to bottom
Last changed on -
Solved by marajade
Comments
today, 06:16 by marajade
This was a mental workout for me but also a ton of fun! Thanks for the puzzle!
