Mod-10 Killer
(Published on 3. December 2025, 10:02 by Vara9850)
RULES
1. Normal sudoku rules apply. 2.(Mod-10 Killer) Digits in a cage do not repeat and sum to a number, the remainder of which divided by 10 is given in the top-left corner of the cage.
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Solution code: Row 4
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Solved by Yaoning, MonsieurTRISTE, psninn, SEPHEN, LabRat, Ste1729, Gribba Bibba, Aaravos, Hierophis69, luoji, Thuna, Photyne, Killer-Ly , IMAY1990, Thibaa, actboy168, matiasv5, ananth, phono, NEWS, JVA, ... Uhu, brandorando, L00ping007, Vaurien, clapslat, CitrusGremlin, NotSoMagnifique, abihummel, GorgeousNicko, Chiefredhawk, NeroChaos, teuthida, jgarber, Ol-Jay, Frank Puzzles, stafen, Counterfeitly
Comments
on 4. December 2025, 11:56 by Vara9850
@Aronana
eg. If one killer top-left corner write 3,it means may be 3, 13, 23, 33 or 43.
Another eg. If one killer contains 1, 2,5 and 9, 1+2+5+9=17, the top-left corner is 7, because the last digit of 17 is 7.
on 4. December 2025, 07:44 by Aronana
Helped me teach my little one about modular 'rithmetic! Thanks Vara
on 3. December 2025, 21:25 by VitP
after finding the REGION that gives the break-in, and dealing with the ramifications, you need to transition to working out the rules of arithmetic in modulo space
