Logic Masters Deutschland e.V.

Solo

(Eingestellt am 23. November 2025, 10:00 Uhr von Kaktuslav)

Link to SudokuPad: https://sudokupad.app/afjrj9tfa5



Rules: Normal sudoku rules apply.

Solo cages: The digit in a cage counts how many of the (up to nine) 3×3 squares that include the caged cell contain no other instance of that digit.

E.g., if R2C3 = 4, then among the six 3×3 squares that include this cell, exactly four contain no other 4.

Lösungscode: Row 5

Zuletzt geändert -

Gelöst von Piff, Qodec, Franjo, flutchman, peterkp, johnreid, DragonEgg, Krisonium, QuiltyAsCharged, humm42, MixedMathialArts, Ikke Moon, karlmortenlunna, Mennoo_, smckinley
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Kommentare

Zuletzt geändert am 25. November 2025, 22:29 Uhr

am 25. November 2025, 20:33 Uhr von Ikke Moon
Great explanation of the rules. Thinking about them for more than 15 minutes and still don't know what you mean (non native speaker, must be my handicap).
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K: Let me try to elaborate — I hope this will be helpful. For each cage (say containing the digit N) in the grid, consider all 3×3 squares of nine cells that contain this cage. There are at most nine such squares, but possibly fewer (e.g., R2C3 is included in only six such squares — those with top-left cells in R1C1, R1C2, R1C3, R2C1, R2C2, and R2C3). Among these 3×3 squares, there are exactly N that contain just one occurrence of the digit N (i.e., this digit does not repeat within this 3×3 square outside the considered cage).

am 24. November 2025, 19:50 Uhr von flutchman
Brilliant idea and great execution. Nice puzzle.

am 24. November 2025, 14:24 Uhr von Franjo
Interesting and unusual constraint, I needed a second attempt to find my way through - and gave 4*. But I really did enjoy it a lot. Thank you very much for creating and sharing this great puzzle.

am 23. November 2025, 15:15 Uhr von Qodec
Refreshing and very interesting!

Schwierigkeit:4
Bewertung:98 %
Gelöst:15 mal
Beobachtet:1 mal
ID:000Q9D

Rätselvariante Neu

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Lösungscode:

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