Rank Up 20.Farkov - Arrow
(Eingestellt am 18. Oktober 2025, 11:27 Uhr von Farkov)
This little setup came to me as I was drifting off last night. Apparently I've been playing too many of ThePedallingPianist's amazing Rank Up series, which can be found here, and which was obviously the inspiration for this :)
Rules:
Sudoku:
Within the main grid (inside the thick border), fill every cell with a digit from 1-5 such that digits do not repeat in a row or column.
Full Rank:
A value in an external cell represents the rank of the number formed by reading the digits in that row or column from that direction, where (1) is the lowest such row or column and (20) is the highest.
Arrows:
Values on an arrow sum to the value in the attached circle.
N.B. If two ranks are tied, the value in both external cells is the lower of the two ranks being shared. For example, if the lowest four ranks are '12453', '13524', '13524' and '15432', the values in the relevant external cells would be (1), (2), (2) and (4) respectively.
Lösungscode: Row 2 of the internal grid.
Kommentare
am 5. November 2025, 02:52 Uhr von SanFranSam
Not too easy not too hard. Remembered Simon's approach to figuring out the how the first digit relates to the rank.
am 27. Oktober 2025, 03:35 Uhr von Tuanzi
Very nice! I love it!
am 21. Oktober 2025, 20:45 Uhr von dzamie
Quite possibly the most approachable of this series I've seen so far, without being entirely trivial. I enjoyed it a lot! For once, I didn't have to try to juggle comparing half a dozen ranks :P
am 19. Oktober 2025, 17:36 Uhr von wuc
Not too easy. I see it as one of the approachable in the series. Great addition thx.
am 19. Oktober 2025, 06:12 Uhr von Farkov
Slight change to the puzzle link.
am 18. Oktober 2025, 13:51 Uhr von Zibl
Was toying around with the same idea of a long arrow, so darn you for being faster! ;)
Great little snack! :)
@Zibl Thanks. My only concern was that it might be too easy. But I thought it might be nice for people new to these puzzles, and it doesn't play out *completely* trivially :)
