Logic Masters Deutschland e.V.

Self-Contained

(Eingestellt am 30. September 2025, 21:27 Uhr von Ennead)



Normal sudoku rules apply.

In each cage there must exist a pair of orthogonally connected cells (a domino) that, when read left-right or top-bottom, give the total of all cells in that cage.

Digits must not repeat in cages.




Play on SudokuPad


Lösungscode: Row 5 followed by column 5 (18 digits)

Zuletzt geändert am 1. Oktober 2025, 07:38 Uhr

Gelöst von OutOfMyMindBRB, Exigus, Ragna, miranda_9, SKORP17, Piff, dzamie, Killer-Ly , Myxo, paranoid, Mad-Tyas, steperlich, galgamer, Fool on Hill, yttrio, ManuH
Komplette Liste

Kommentare

am 7. Oktober 2025, 22:15 Uhr von yttrio
Really cool puzzle! A couple of tricky steps, but most everything flowed superbly once you comprehend the consequences of the rule set!

Zuletzt geändert am 2. Oktober 2025, 16:53 Uhr

am 1. Oktober 2025, 10:02 Uhr von Exigus
Very cool. Did not think that ruleset could be enough to disambiguate everything, but it solved smoothly (with a little bit of arithmetic). Thanks!

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Thanks for solving and for your comment! Glad you enjoyed the puzzle.

Zuletzt geändert am 1. Oktober 2025, 07:43 Uhr

am 1. Oktober 2025, 05:07 Uhr von rameshsrivats
Fantastic puzzle. Enjoyed it all the way from the start to end. Till I hit the solution code :) 18 digits, and I don't think it is working.
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Thanks for solving the puzzle. Glad you enjoyed it. The code has now been fixed.

Zuletzt geändert am 1. Oktober 2025, 09:14 Uhr

am 1. Oktober 2025, 01:33 Uhr von OutOfMyMindBRB
Beautiful setting and logical flow - thanks :-)

Zuletzt geändert am 1. Oktober 2025, 07:40 Uhr

am 1. Oktober 2025, 00:30 Uhr von deltameth
Could you check the code please. Mine doesn’t fit though the app says that I solved correctly.
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Thanks for solving. The code was incorrect. Now changed.

Zuletzt geändert am 1. Oktober 2025, 07:39 Uhr

am 30. September 2025, 22:47 Uhr von SKORP17
Code?
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Thanks for Solving. Sorry about the code! Now changed.

Schwierigkeit:4
Bewertung:90 %
Gelöst:16 mal
Beobachtet:0 mal
ID:000PG2

Rätselvariante

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Lösungscode:

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