At one stage, you must consider which two digits share an S-cell in box 3. The two cases that are hardest (but in my opinion most interesting!) to disprove are:
a) 3 and 4: If this went in column 1, then the 0 in column 3 would be missing the same digit in its box as its column, and vice versa if the S-cell went in column 3;
b) 6 and anything: Wherever this S-cell goes, it would share a column with a cell that must be either 6 or an S-cell, and this would break both options.
The X clue quickly reduces the options such that the only moderately difficult case to disprove is 3 and 5. It also makes the rule requiring each to be missing different digits in its row, column and box redundant across the whole puzzle, which is a shame, but may be for the best!
Solution code: Values in row 1 (a cell's value is the sum of its digits), left to right
yesterday, 00:43 by eladv
Thank you TPP! This was a really cool puzzle! It took me a long time to solve, but I think it inherently is not that hard (at least not with the X clue. I didn't try to solve it without the X! :) )
Difficulty: | ![]() |
Rating: | N/A |
Solved: | 3 times |
Observed: | 0 times |
ID: | 000P9M |
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