Powers of Two
(Published yesterday, 08:00 by Kaktuslav)
Rules: Normal sudoku rules apply. Logarithmic arrows: Bulbs contain pairwise different (i.e. non-repeating) powers of two (1-, 2-, or 3-digit numbers written in decimal). If a bulb contains 2^x (2 to the power x), the digit on the attached arrow must be x.
Solution code: Row 4
Comments
today, 03:55 by dzamie
Math :)
yesterday, 18:35 by Franjo
From a setter’s perspective you did very well in finding a way to put those nine L.A.‘s into the grid that leads to a unique solution. From a solver’s view it was extremely easy to fill all the bulbs and arrows and get an easy-to-solve standard sudoku. Anyway, thank you for sharing this interesting - experiment(?).
yesterday, 18:30 by Supertaster
Each bulb, read as a single number left-to-right, is a power of two. The power is pointed to by the arrow.
For example, 2^7 = 128, so you might have a bulb that reads 128 and points to a 7.
yesterday, 18:26 by sfield
"pairwise different" would make sense to distinguish between {2,4} and {4,2}. But one of those is a valid {x,2^x} pair and the other isn't. So including the term pairwise just makes it confusing. I tried solving it for a while before realizing each power had to be different and then it became easy.
yesterday, 18:17 by Kaktuslav
Clarified rules
yesterday, 18:09 by Dermerlin
Is it really each bulb's SUM that is a power of 2???
I'd guess it's the number writeen in the bulb and not the sum.
yesterday, 15:42 by Grumpy
Yeah, the rules are a bit hard to grasp at first.
But essentially:
- Each bulb has a different sum
- Each bulb's sum is a power of 2
- The number on the arrow is the exponent to raise 2 to, to get the sum in the bulb. For example: 4<-(16), since 2^4 = 16
yesterday, 13:57 by Lego7656
pairwise? what pairs?
