Logic Masters Deutschland e.V.

Scattered

(Published on 30. July 2025, 00:00 by Mattisahuman)

I am extremely proud of this puzzle. Setting this was extremely fun and rewarding so I hope the solve is the same.

Rules:

Normal Sudoku Rules Apply: Place the digits 1-9 in every row, column and box once each.

Arrows: Box borders have chopped all arrows into 2 sections and all arrow segments have been scattered throughout the grid. It is your job to deduce which arrow circles connect to which arrow tips. The direction in which lines enter/exit boxes is purely aesthetic. All arrow circles need to connect with exactly one arrow tip. The number in the circle of an arrow indexes the box number of its arrow tip and no two circles index the same arrow tip. Digits along an arrow must sum to the digit in its circle.

Sudokupad

Solution code: The digits in arrow circles, starting with box 1, then box 2, etc.

Last changed on on 30. July 2025, 07:28

Solved by taco.bella, Dermerlin, marcmees, allama, JoeyJoeJoe, MontyPython'sHolyAle, SKORP17, taxman144, hige, chis_r, paranoid, Nagesh, Jodelbanane
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Comments

on 30. July 2025, 12:09 by VitP
very nice.

with all those HYPERSPACE BYPASSes, the vogons must have been active.

on 30. July 2025, 08:12 by JoeyJoeJoe
00:51:59 for me - took me a while. Didn't read the part about the indexing,

on 30. July 2025, 07:28 by Mattisahuman
Clarified the solution code

Last changed on 30. July 2025, 07:25

on 30. July 2025, 06:19 by Mozart40
I'm not entirely sure I understand the rules. I thought the boxes were mixed. But that doesn't work because R4C1 requires a connection in the third cell of a box, and that doesn't exist. Should the boxes be rotated, or should it work differently?

The locations of the arrows have no impact on where they connect to arrow tips

Last changed on 30. July 2025, 03:03

on 30. July 2025, 03:00 by Dermerlin
very nice puzzle. Thx for posting!
I'd recommend a declaration of the solution code.
Something like "box for box" or "boxwise".
The way it is written i tried to put in
r2c3 r2c8 r3c6 ... because in reading order r2c8 is before r3c6...
just my 2 cents. Perhaps i am the only one to understand it this way.

Difficulty:2
Rating:N/A
Solved:13 times
Observed:3 times
ID:000OFP

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