Crystalline Entity
(Eingestellt am 22. Mai 2025, 13:23 Uhr von IcyFruit)
Normal sudoku rules apply.
A digit in a circle indicates the number of times that digit appears in either a circle or a square.
Digits along an arrow sum to the digit in the attached circle.
Lösungscode: Columns 1 and 8
Kommentare
am 27. Juni 2025, 21:11 Uhr von Exigus
That was a really clever setup. Thanks!
am 29. Mai 2025, 00:43 Uhr von Jackler
Cool logic. This is similar to something I solved a while back that uses the idea of one way logic instead of an absolute restriction on the 45 being the max into both circles and squares. And the idea on how to prove that only 1 digit is missing from the circles and then what that digit is...that is perfect and raw sudoku logic. Makes me a little jealous of how some people think and set these things up.
That 40 minute solve felt like 10 minutes. Time flew by.
am 28. Mai 2025, 09:49 Uhr von Justalilguy
I feel proud of figuring this one out.
am 28. Mai 2025, 06:09 Uhr von blueberrypug
very nice puzzle and I appreciate the ST:next gen reference!!
am 25. Mai 2025, 20:43 Uhr von killer_rectangle
@Romeo:
It is definitely possible for digits in circles to be bigger than 6. If there is a 7 in a circle, for example, then there are seven 7s in circles and squares. Thus there would have to be at least one 7 in a square.
am 24. Mai 2025, 15:57 Uhr von Romeo
square are distributed across 6 rows, and circles are distributed across 6 columns. This means that the numbers in the circles cannot be greater than 6. How should we fill in the middle block？
am 23. Mai 2025, 13:35 Uhr von PierreTombal
Completely misjudged this one as there were obvious restrictions, like it being impossible to keep any single digit away from all of the marked cells. The result was that I struggled a lot and broke the puzzle several times as I neglected to note that the restriction acts on more digits than I had originally taken into account.
Me being a donkey's ass does not qualify a 5* rating though, so I rated it 4*. Thank you for the lesson well served.
am 22. Mai 2025, 21:33 Uhr von henrypijames
@killer_rectangle: The puzzle isn't broken because what's true for the circles isn't necessarily true for the squares - there can be digits in squares that don't appear in circles, in which case their occurrence in the squares isn't limited (if 1 doesn't appear in circles, it may appear 9 times in squares).
am 22. Mai 2025, 18:21 Uhr von Snookerfan
Fantastic puzzle! Full of fresh logic, very satisfying. Thank you
am 22. Mai 2025, 17:35 Uhr von killer_rectangle
Can someone clarify the rules for me? My understanding of the rules is that if a 9 appears in a circle, then the number of 9s in circles plus the number of 9s in squares is 9. However, under that interpretation, the puzzle appears to be broken.
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You are interpreting it correctly
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Why isn't the puzzle broken? I count 31 circles and 16 squares, for a total of 47. Since 47 > 45, the puzzle is broken.
am 22. Mai 2025, 15:52 Uhr von Jolly Rogers
Sometimes your puzzles deserve a 6 star rating for difficulty, but this is not like those. Felt like approachable logic for 5 stars, and fairly intuitive for where the tension lies. Very nice and rewarding solve, thanks!
