Logic Masters Deutschland e.V.

Shoutout to sirxemic for supporting me in coding a new type of constraint into his sudoku maker app.

Solve here on Sudokupad

Rows and columns with an outside clue each contain a "balance beam" of 5 cells length, marked as (part of) a cage. If there is a 6th, separate cage marked cell in the row/column, it does not belong to the beam of this row/column. Cells can however belong to the 5-cell beam of both the row and column they are in.

The balance of a beam is calculated by adding together digits in each half (the middle cell is ignored), each digit weighted according to the lever given by its distance from the middle of the beam, i.e. on a 5-cell beam the outermost cells count x2, the 2nd and 4th cell count x1 to their respective side's "weight". Adding the outside clue to the left / top half of the beam (with weight x1) brings the beam into balance, i.e. makes the sums on each half equal.

Example: with an outside clue 5, one valid solution for the beam is 2-7-x-8-4 because 2*2+7+5=16=8+2*4.

Cells connected by a Black Kropki dot are in a ratio 1:2. Not all dots are given.

Adjacent digits along a green line (German whisper line) have a difference of at least 5.