U-Bahn Under Arrows
(Eingestellt am 7. April 2025, 05:57 Uhr von wooferzfg)
The rules for this puzzle are similar to a series by Zzzyxas. There is also a puzzle by KNT with similar rules.
If you are unfamiliar with U-Bahn, here is a guide that covers the core logic.
The first diagram is a standard U-Bahn. Draw a loop network through the centers of some cells, which may branch or turn, but may not have any dead ends. A clue outside the grid indicates how many times the corresponding line shape (i.e. a cross, branch, straight line, or turn) appears in the corresponding row or column, irrespective of the line shape's rotation.
The second diagram is a 6x6 Latin Square. Place the numbers from 1 to 6 exactly once in every row and column. Numbers on arrows must sum to the number in the circle.
The third diagram indicates exactly how many times a cell of the Latin Square contains the given number and the same relative cell of the U-Bahn contains the given line shape.
Lösungscode: For each column in the U-Bahn grid except the last, from left to right, the number of lines leading to the right from that column
Kommentare
am 11. April 2025, 16:57 Uhr von MaizeGator
Incredible logic and construction, especially with so few clues.
(answer check didn't work for me, but the solution code did)
am 10. April 2025, 06:11 Uhr von Agent
Awesome puzzle, very clean logic all the way through, I enjoyed every step!
am 8. April 2025, 16:31 Uhr von jessica6
I hardly realized what to do with the clues. But when I found out, the puzzle was nice.
am 7. April 2025, 23:50 Uhr von Piatato
Fun!
am 7. April 2025, 07:15 Uhr von KNT
:)
