Logic Masters Deutschland e.V.

The amicable prodigy

(Eingestellt am 5. März 2025, 05:40 Uhr von NicoD)

The amicable prodigy by Nicolas Duhail.

This is part 2 of my 6x6 friendly cells trilogy.
Part 1: Moody friendship
Part 3: Pygmy Python

Rules
Normal sudoku rules apply.
In this puzzle, half of the cells are "friendly".
A cell is "friendly" if it contains its row, column, or box number.
Cells separated by a knight's move cannot contain the same digit.
In the finished grid, each 2x2 square of cells has to contain at least one low digit (1/2/3) and one high digit (4/5/6) [Global entropy].
Digits separated by an X sum to 10, and they are ALL given.

Optional rule to make the puzzle easier:
Digits separated by a V sum to 5, and they are ALL given.

Play this puzzle on SudokuPad

Lösungscode: Row 2

Zuletzt geändert am 6. März 2025, 03:59 Uhr

Gelöst von SincereEngineer, pms_headache, gdc, Snookerfan, SKORP17, zeniko, mego, faisalaak, Crusader175, annnz, -Tsigje-, benisjammin
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Kommentare

am 6. März 2025, 03:59 Uhr von NicoD
Edit: added links to parts 1 and 3.

Zuletzt geändert am 5. März 2025, 14:24 Uhr

am 5. März 2025, 11:18 Uhr von Snookerfan
Very nice. I found some of the deductions a little bit a long chain, therefore hard to spot. The global entropy did some heavy lifting, which I liked a lot. In the end everything came together really well. Thank you
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ND: Thanks, glad you enjoyed.

Schwierigkeit:3
Bewertung:N/A
Gelöst:12 mal
Beobachtet:6 mal
ID:000M9E

Lösung abgeben

Lösungscode:

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