Logic Masters Deutschland e.V.

Fractured Lines

(Eingestellt am 10. Januar 2024, 16:10 Uhr von Bonehead)

This is Sequel to Whose Line is it Anyway? which was well received. The implementation here is a tougher solve though.

Rules.

Classic sudoku rules apply.

Cages total to the value shown in their top left corner. Digits in cages may repeat if allowed by other rules.

Digits separated by a white dot are consecutive.

Adjacent digits along a green line must differ by at least 5.

Blue lines contain all of the digits from 1 to 9 with only one of the digits repeating. The repeating number may be different on each blue line and is to be determined .

The Puzzle.

CTC version with solution check here

Penpa+ version with answer check here


Please enjoy and comment if you like this. It is appreciated. Thank you.


Lösungscode: Zeile 3, dann Spalte 7 mit 18 Ziffern, ohne Leerzeichen


Gelöst von jalebc, SKORP17, StefanSch, andreatetta, mcc, Juiceshack, dskaff, Nagesh, peterkp, Jodelbanane, flipout, Fredxl, AvonD, Jlrice2, Fra314, paranoid, DiMono, RockyRoer, Playmaker6174, bolgat, onbu, OGRussHood, mezkur7
Komplette Liste

Kommentare

am 20. Februar 2024, 14:03 Uhr von Playmaker6174
The only cautious thing one needs to keep in mind is that digits *can* repeat within a cage. Other than that, it’s pretty smooth and manageable.

Zuletzt geändert am 19. Januar 2024, 09:54 Uhr

am 16. Januar 2024, 19:06 Uhr von Fra314
Great puzzle, this constraint is a cool diversion from the usual rules. Well done!
@Fra314. Thank you. I will use this or a similar rule in future. It has legs.

Zuletzt geändert am 16. Januar 2024, 21:49 Uhr

am 13. Januar 2024, 11:30 Uhr von Fredxl
Ooooh, I wasn’t sure about this rule set, but I ended up enjoying it greatly! My thanks are directed your way :)
@Fredxl. Thank you. This ruleset has a lot of possibilities

Zuletzt geändert am 12. Januar 2024, 00:03 Uhr

am 11. Januar 2024, 23:13 Uhr von peterkp
Thanks for the nice puzzle. I suggest you hide the comment about the repeated digit, since that will be a spoiler for other solvers.
@peterkp yep, probably a good idea. Done. And thanks for the solve.

Schwierigkeit:3
Bewertung:87 %
Gelöst:23 mal
Beobachtet:0 mal
ID:000GIA

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