Logic Masters Deutschland e.V.

1234 (anti-king,anti-knight,negative XV)

(Eingestellt am 22. Juni 2023, 10:58 Uhr von William Cheese)


Rules:
  • Normal sudoku rules apply.
  • X/V Two digits separated by an X must sum to 10. Two digits separated by a V must sum to 5. (These digits are orthogonally adjacent.)All possible XV are given.
  • Anti-knight A square must contain a digit different from every other square a knight’s move away (2 over and 1 across).
  • Anti-king A square must contain a digit different from every other square a king’s move away (sharing a vertex).

F-puzzles link: Click Here

Lösungscode: Column 1, row 9

Zuletzt geändert am 22. Juni 2023, 11:36 Uhr

Gelöst von Senip, annnz, Lorff, jalebc, VeTaurus, Qodec, XhcnoirX, Fishhh, sbc, kublai, flaemmchen, jgarber, belfieldtj, marcmees, thoughtbyte, dodomos, zuzanina, 333sudoku333, bnoblett, asver, Hondor64, ... ManuH, Carolin, Unknown, zhergan, jhuijts, PinkNickels, Awoobledoople, Thomster, saskia-daniela, 0123coolkid, PippoForte, JSmoove1099, chain.reader, dingledork, LachyDachy, mattnburris, Montikulum
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Kommentare

am 14. Januar 2024, 00:14 Uhr von chain.reader
awesome! amazing how this even works

am 30. Juni 2023, 20:07 Uhr von 99%Sneaky
Nice interplay between the constrains.

am 26. Juni 2023, 03:20 Uhr von sacklunch
Great puzzle, very interesting. The solution code worked for me.

am 23. Juni 2023, 10:51 Uhr von KcDaRookie
Same as starstorm. Have a solution but the code isn't accepted.

am 22. Juni 2023, 22:59 Uhr von Timwi
Awesome puzzle! Not as easy as the rating suggests, but I enjoyed it thoroughly.

Here’s a link to play this puzzle on Zinga: https://zinga.timwi.de/czHfllCJdMZR8zXeHZVbh6

am 22. Juni 2023, 16:53 Uhr von Starstorm
The solution code doesn't seem to work, even though I have a complete grid that satisfies all rules

am 22. Juni 2023, 11:36 Uhr von William Cheese
edit

Zuletzt geändert am 22. Juni 2023, 11:33 Uhr

am 22. Juni 2023, 11:20 Uhr von jalebc
code?
-----
Did the code not work?

Schwierigkeit:1
Bewertung:82 %
Gelöst:89 mal
Beobachtet:2 mal
ID:000E90

Lösung abgeben

Lösungscode:

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