Logic Masters Deutschland e.V.

A Fillomino for the Bees

(Eingestellt am 13. Juni 2023, 19:53 Uhr von mathpesto)

Rules:

Divide the cells in the grid into polyominoes so that no two polyominoes of the same size share an edge. Each fillomino cell contains a number equal to the size of its polyomino. The number in a cell with an arrow equals the amount of borders between polyominoes in that direction. (Edges of the grid do not count towards this total.) If a cell contains multiple arrows, each direction counts separately (e.g. if a cell containing a 2 has an east arrow and a southwest arrow, there are 2 borders in the east direction and 2 borders in the southwest direction).


Solve online:

Penpa

Lösungscode: main positive diagonal, from rightmost cell in top row to leftmost cell in bottom row (15 numbers, no spaces)

Zuletzt geändert am 13. Juni 2023, 19:54 Uhr

Gelöst von MicroStudy, Bellsita, KNT, tuturitu, CrippledLamp, Myxo, bolgat, Statistica, RJBlarmo, bernhard, Franjo, cdwg2000, Paquet Voleur, dogfarts, sth, misko, dennischen, Mr_tn, davidxxy, Jaych, Jesper, Nylimb, Vebby, Christounet, jkuo7, AKernel, ManicVolcanic, kjholt, wand, Chefofdeath, indolentfool, Tacosian, Las4one, crispy16, SKORP17, zhantyzgz, OGRussHood, nottabird, GTLSE, kmoter, Beanie, teff
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Kommentare

am 16. Juni 2023, 12:14 Uhr von Christounet
Sweet :) Thanks !

am 15. Juni 2023, 04:32 Uhr von Paquet Voleur
Bzzzzbzzzzz!

am 13. Juni 2023, 23:30 Uhr von Myxo
Awesome puzzle, so much fun!

am 13. Juni 2023, 19:59 Uhr von MicroStudy
smooth as honey

Schwierigkeit:4
Bewertung:95 %
Gelöst:42 mal
Beobachtet:1 mal
ID:000E5Y

Rätselvariante Hexagonal Polyominos

Lösung abgeben

Lösungscode:

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