Logic Masters Deutschland e.V.

I've been into setting doppelgänger puzzles lately, so I thought I'd share a couple more that I've made. :)

This puzzle is solvable both as a yajitatami and as a yajisan-kazusan.
The yajitatami is easier (which means I like the yajisan-kazusan better).



Yajitatami:
Divide the grid into 1xn regions, where n>1, such that the digit in a clued cell equals the amount of cells in that region as well as the amount of regions seen in the direction of its arrow. There must always be a border directly in front of an arrow, and nowhere in the grid may a cross be formed by borders (four border lines eminating from the same point).
Link to puzzle
Rules and example on puzz.link

Yajisan-kazusan rules: Shade some cells in the grid such that no two shaded cells are orthogonally adjacent and all the unshaded cells form a single connected region. If an unshaded cell has a clue in it, then that clue gives the number of shaded cells in the direction of the arrow. A clue in a shaded cell has no bearing on the puzzle and can be ignored.
Link to puzzle
Rules and example on puzz.link

Both puzzles (Penpa+)
Answer check on shading (Yajisan-Kazusan) and edges (Yajitatami) together.

Enjoy!