Spin Me Right Round
(Eingestellt am 7. November 2021, 15:23 Uhr von Will Power)
Normal Sudoku rules apply. Both main diagonals also have no repeated digits. The two digits on both sides of the X sum to 10. No 2 cells of the same value are a chess king's move apart. The completed patterns for 1's, 2's, 3's and 4's are the same as one another, after rotating the grid 90 degrees around the center cell for each number. The same is true for the patterns of 6's, 7's, 8's and 9's. Example: If R1C1 is a 1, then R1C9, R9C1 and R9C9 are, once each, a 2, 3,and 4, in some order. The pattern for 5's looks exactly the same after rotating the grid 90 degrees in any direction.
Lösungscode: Row 8 and column 8, no spaces. Example: 123456789987654321
Zuletzt geändert am 29. Dezember 2021, 12:03 Uhr
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Kommentare
am 8. September 2022, 00:33 Uhr von Schesam
Solved it and after i realized there was a King-constraint. Wasnt needed at all, but was fun
am 28. Dezember 2021, 10:23 Uhr von BarginsGalore
I assume the x is meant to mean the two digits on it add up to 10 but that's not clarified in the rules.
am 10. November 2021, 22:49 Uhr von Will Power
ctshirk7: I assume you mean boxes 2, 5 and 8. The only way for this deadly pattern to matter is if you do not observe the correct sequence for 6, 7, 8 and 9 as you move about the center. Since the right center cell of box 6 is a 7.... then you should know whether a 6 or 8 goes in the bottom center in box 8.
