Logic Masters Deutschland e.V.

Rotationally Symmetric Antiknight Arrows

(Eingestellt am 30. September 2021, 05:55 Uhr von kolot)

Here is one of my favourite puzzles which may require some coloring. I hope you enjoy it. Any feedback is highly appreciated!

RULES: Normal sudoku rules apply. Digits along an arrow must sum to the number in the corresponding circle. Digits may repeat along these arrows if allowed by the other rules. Cells separated by a knight's move in chess cannot contain the same digit.

Solve on CTC app

Solve on f-puzzles

Lösungscode: Row 1 followed by column 9

Zuletzt geändert am 28. April 2022, 14:28 Uhr

Gelöst von Ood, Elliott810, SKORP17, Tilberg, Dentones, cfop, rmahus, polar, ___, legstretch, PulverizingPancake, Cowbear, antiknight, butch02, cdwg2000, zuzanina, koba1917, manushand, galgamer, erisman, kaitoJD, ManuH, twobear, Vebby, deltameth, Sewerin, Statistica, karen_birgitta, by81996672
Komplette Liste

Kommentare

am 28. April 2022, 14:28 Uhr von kolot
CTC app link is added.

Zuletzt geändert am 1. Oktober 2021, 15:33 Uhr

am 1. Oktober 2021, 15:05 Uhr von cdwg2000
Very nice!difficulty:~3.5
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Thank you! :-)

Zuletzt geändert am 1. Oktober 2021, 00:40 Uhr

am 30. September 2021, 21:52 Uhr von polar
Very nice puzzle! Difficulty wise I would say a 3.5-4.
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Thank you so much! I was not sure whether I should select 4 stars or 5 stars for the difficulty. I chose 5 but also wrote 4.5 in the explanation above so that the solvers understand that it is not extremely difficult. I will not be surprised if its difficulty is rated by the solvers as 4 stars at the end.

Zuletzt geändert am 30. September 2021, 09:47 Uhr

am 30. September 2021, 08:38 Uhr von Elliott810
Absolutely brilliant puzzle! The relations between the arrows and the anti-knight constraint feel like magic. Thx for sharing:)
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Thank you for your kind comments! I am happy to see that you enjoyed it.

Schwierigkeit:4
Bewertung:90 %
Gelöst:29 mal
Beobachtet:3 mal
ID:0007Q9

Variantenkombination Online-Solving-Tool

Lösung abgeben

Lösungscode:

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