Logic Masters Deutschland e.V.

Blind Spot Sudoku 1

(Eingestellt am 24. November 2020, 14:57 Uhr von Wecoc)

This is a new type of puzzle I made some time ago.

Sudoku Rules apply. The even digits represent pointers: Following the Numpad, 2=down, 4=left, 6=right and 8=up. In each 3x3 box no pointer can see another pointer of the same box.

Example: Valid vs Invalid box


Puzzle:

Solve it here: https://f-puzzles.com/?id=y4v9ro8h

Lösungscode: Row 1 and row 4 without spaces (18 digits)


Gelöst von Fedo , SirWoezel, wilsig, chippers, Sktx, Ours brun, SKORP17, rimodech, fuxia, dandbdi, john9, MavericksJD, dm_litv, soroush, SenatorGronk, doppelganger, marcmees, ibogdank, cdwg2000, brandon_bot, ... scarlettplusnoir, Joo M.Y, mango, puffy2005, Raistlen, jgarber, rl_2203, adam001, sabsp, ParaNox, irq, cfop, jalebc, Crul, JSmoove1099, Uhu, zrbakhtiar, Carolin, Jordan Timm, rares495
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Kommentare

am 29. März 2021, 22:02 Uhr von rl_2203
sehr schönes und leichtes Sudoku, nette Idee mit den Spezialregeln - danke fürs Erstellen

am 9. Dezember 2020, 18:09 Uhr von Eva_m394
Nice idea, it has great potential! Can't wait to solve harder puzzles based on these pointer digits. Thanks!

am 30. November 2020, 05:51 Uhr von Mufasa
Cool concept. Had to keep reminding myself to use the negative constraint.

am 26. November 2020, 04:37 Uhr von panthchesh
Thanks for the puzzle! :)

am 24. November 2020, 21:50 Uhr von Wecoc
I'm glad you liked it. This one is pretty easy since it was meant to be an introduction to the ruleset, soon I'll post a more challenging one.

am 24. November 2020, 17:15 Uhr von Sktx
Very nice idea ! I would say 2 stars for the difficulty, but very satisfying solve, and the idea has great potential for interactions in harder puzzles (off the top of my head, irregular boxes ? magic squares ? diagonal odd pointers ? length-limited pointers ? cage-contained pointers ?)

am 24. November 2020, 16:04 Uhr von Fedo
Nice one!

Schwierigkeit:1
Bewertung:85 %
Gelöst:91 mal
Beobachtet:8 mal
ID:0004S4

Standardrätsel Rätselvariante Neu

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Lösungscode:

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