Even The Odd Killer
(Eingestellt am 29. August 2020, 13:48 Uhr von tzael)
Es gelten die normalen Sudoku-Regeln. Es gelten die Regeln für Killerkäfige. Ziffern in einem Käfig müssen sich zur Summe summieren und wiederholen sich nicht.
Außerdem sind einige Käfige markiert.
Mit e gekennzeichnete Käfige enthalten nur gerade Ziffern.
Mit o gekennzeichnete Käfige enthalten nur ungerade Ziffern.
Alle mit e oder o gekennzeichneten Käfige haben eindeutige Ziffernkombinationen.
Schließlich zeigt ein weißer Kreis die kleinste Ziffer in diesem Käfig an.
Lösungscode: Zeile 8, 9
Kommentare
am 11. Dezember 2020, 00:32 Uhr von SudokuExplorer
A lovely parity sudoku, thanks :-)
am 30. August 2020, 19:34 Uhr von Quarterthru
ONLY the e / o cages must have different digits. Numbered cages do not follow this restriction nor do they restrict the e/o cages.
am 30. August 2020, 18:39 Uhr von Narayana
@geronimo92:
Take a look at my comment below yours specially the part that says for future solvers. I think that will clarify the rule. The puzzle IS interesting. Take a second look. :)
am 30. August 2020, 17:44 Uhr von geronimo92
Sorry but i understood the rule correctly (only cages marked with e or o ) but i still remain with contradictions again and again.... no matter what, let's give up and look forward for another more interesting one....
am 30. August 2020, 08:15 Uhr von Narayana
Once you understand what you have to do the puzzle is nice and easy but the most powerful rule is poorly explained. Which resulted in 2 full restarts, plenty of contradictions and me shouting at the screen when I finally figured it out.
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For future solvers:
When they say “All cages marked with e or o, have unique combinations of digits.”
That means if a MARKED cage contains for example the digits {ABC} there can NOT exist another cage of the same size containing the exact same set of digits. Here order does not matter the set {B A C} is still the same as the set {ABC} thus {BAC} is not allowed in another cage. However {ABD} IS allowed.
If you heavily use the power of this rule you should encounter a smooth solve.
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For people curious about what I did that gave me such a head ache: I interpreted unique combination as referring to the “pencil marks”
For example the 8 cage is not marked so it can have several combinations for pencil marks like 1+7 or 3+5 but the e cages in column 4 are both marked
So the must give numbers that can only made in one way with even numbers
So out of the combinations:
2 + 4 = 6
2 + 6 = 8
2 + 8 = 10
4 + 6 = 10
4 + 8 = 12
6 + 8 = 14
The cage value 10 is forbidden since it results from two different pencil marks… Clearly this was not the intent of the problem but some how it made sense to me :(
