The standard Moon-or-Sun rules apply.
Lösungscode: Row 9 (left-right). Use L for cells with a bend in the loop, I for cells with a straight in the loop, and X for cells without loop.
am 10. September 2020, 17:46 Uhr von Lucx
Very nice one! Indeed you should add to the description that each room holds at least one sun or one moon.. Thank you, I really liked that one
am 1. August 2020, 14:17 Uhr von Dotty
Thanks, I've resolved your 2x1 dominoes and it make me understand
am 1. August 2020, 13:25 Uhr von athin
@Dotty: The alternative way to see this puzzle is to put either sun or moon in each empty cells, so all cells are containing a single element. Then, draw a loop visiting all rooms. In one room the loop visits all moons without visiting any suns, then in the next room they alter: the loop visits all suns without visiting any moons, etc.
am 1. August 2020, 10:52 Uhr von Dotty
I think there are more than 1 solution, or there is something I don't understand in rules. How do we have to considere rooms with no sun or moon ? Can I pass on a moon, then in 1 empty room, then on a sun ? Or do we have to imagine alternate sun and moon in empty rooms ?