(Eingestellt am 18. Juni 2020, 09:07 Uhr von Michal58)
An easy puzzle just to introduce the idea.
Normal sudoku rules apply. In addition, the 25 shaded cells form a (45° rotated) 5×5 latin square of numbers 1-5. That is, each gray diagonal run of 5 cells must include each number 1-5 exactly once.
I wanted to create a puzzle with two sudokus (or just latin squares) overlaping.
In this setting though, there are just two (up to permutaion of digits 1-5) ways of fulfilling the 5×5 latin square constraint within a sudoku grid. Given that you need to specify at least four out of the digits 1-5 and at least three out of 6-9 it makes the puzzle quite straightforward, especially since I went for a symmetric design.
In the future I would like to create a puzzle where it's not a priori known what subset of digits 1-9 form the latin square and make it not symmetric so that it is more interesting.
Lösungscode: 1st and 8th row
Gelöst von cornuto, marcmees, NikolaZ, Rollo, zorant, glum_hippo, cdwg2000, Rotstein, Osh Tirola, SirWoezel, stefliew, geronimo92, Kekes, 0123coolkid, Nothere, KlausRG, Julianl, saskia-daniela, Yohann, WAW, ... Zzzyxas, mango, skywalker, logik66, Rollie, moss, zuname, HumveeRuin, Xavien , MatthewDonovan, Madmahogany, DukeBG, bob, Joo M.Y, Monso, jplank, jessica6, L77059, FlareglooM, ManuH, ffricke, Uhu
Zuletzt geändert am 18. Juni 2020, 19:38 Uhr
am 18. Juni 2020, 19:35 Uhr von cam
This is the best coffee break puzzle I've ever seen. It's elegant and beautiful--a puzzle I want to come back to and solve again! Thanks.
Edit: I, along with probably a lot of people, have considered putting a 4x4 sudoku within a puzzle. Unfortunately it's easy to see that this can't be done. How unsatisfying! This puzzle makes up for that!
am 18. Juni 2020, 11:11 Uhr von Rollo
Super idea and very very nice design!