Symmetric Unequal Sudoku with Renban Groups
(Eingestellt am 30. Juli 2010, 09:32 Uhr von zhergan)
Place the digits 1 to 9 in every row, column and 3x3 standard block. Cells that are 180° symmetric to each other cannot have same digits (e.g. R[n]C[k] can never have the same digit as R[10-n]C[10-k]). Besides grey painted connected cells form renban groups. These groups must hold consecutive numbers, in any order.
Lösungscode: First enter the contents of row 2 and column 8, then give sum of the digits for each of 4 renban groups increasing in order.
Kommentare
am 15. August 2021, 23:18 Uhr von zhergan
Tags revision..
am 30. Juli 2010, 16:55 Uhr von HaSe
(C1R2) = (C9R2) is allowed
so so !?!
@HaSe: Hi Hartmut, I really didn't notice the two cells are on the same row since I was dealing with something else:)) I corrected my comment about it. Ooops:)
am 30. Juli 2010, 16:43 Uhr von flaemmchen
@Luigi: Danke!
am 30. Juli 2010, 14:42 Uhr von Luigi
Diese Regel kann man bildlich auch so verstehen: Keine Zahl darf durch Spiegelung (=Punktspiegelung) an der Mitte auf sich selbst abbildbar sein.
Die Mitte ist hier das Zentrum des Sudoku.
am 30. Juli 2010, 13:53 Uhr von flaemmchen
Könnte mir jemand diese 180°-Regel auf Deutsch erklären? Das wäre sehr nett!
Vielen Dank!
am 30. Juli 2010, 11:49 Uhr von Luigi
Eine sehr interessante Variante. Eine echte Konzentrationsarbeit ohne T&E.
am 30. Juli 2010, 11:02 Uhr von Statistica
The rule is: R[n]C[k] can never have the same digit as R[10-n]C[10-k] for all n, k from 1 to 9 (not both 5 ;-)), which means (point-) symmetric fields to the center-field.
@Statistica: This formulation with n and k is much better I think. I am editing the previous one also. Thanks:)
am 30. Juli 2010, 10:47 Uhr von Luigi
I do not understand the rules. Could you give some more examples of what is allowed or not?
Is (C1R2) = (C9R2) allowed?
Is (C1R2) = (C9R8) allowed?
@Luigi: Hi Peter,
(C1R2) = (C9R2) is not allowed since both cells are on the same row.
(C1R2) = (C9R8) is not allowed also due to the given rule.
Zafer
am 30. Juli 2010, 10:21 Uhr von Statistica
I have problems with the code... BTW: What means 'even diagonally' in the instructions???
OK. My fault, all is correct ;-)
@Statistica: Hi Jörg, you're right 'even diagonally' expression is completely meaningless here. I just copied that part of the text from another puzzle where it is meaningful. I am editing that part in a few seconds.
am 30. Juli 2010, 09:54 Uhr von Realshaggy
Just some nitpicking: What about n=5? :-)
@Realshaggy: Yes this leads us to a contradiction. I think we must assume that n!=5 for this one:))
