A Bouquet of Complements
(Published yesterday, 13:36 by RockyRoer)
The Rules:
- [Sudoku]: Normal sudoku rules apply -- fill every row, column, and 3x3 box with the digits from 1 to 9 once each.
- [Dynamic Fog]: Entering enough correct digits in cells will reveal more of the puzzle.
- [Complements]: A pair of 2-digit numbers read from left to right are circled. This pair of numbers must add to 90. Each time the fog clears, another pair will appear - each time summing to 90.
- [Standard Sudoku Variants]: Some (but not all) of the following standard variant sudoku rules may appear:
- [Killer] Digits in a killer cage must sum to the total given in the upper right corner.
- [Lines] Standard line rules will apply for some common line variants that may appear such as:
- Renban - the digits on the line form a set of consecutive numbers
- Entropic - any three digits on the line cycle through the sets {123},{456}, and {789}
- Modular - any three digits on the line cycle through the sets {147}, {258}, {369}
- German whisper - any two adjacent cells on the line have a difference of at least 5
- Dutch whisper - any two adjacent cells on the line have a difference of at least 4
- Parity - any two adjacent cells alternate between odd and even
- [Pairs]: Standard pair rules will apply for some common pair variants that may appear such as:
- XV - cells separated by X sum to 10 and cells separated by V sum to 5
- Kropki - cells separated by a white dot have a difference of 1 and cells separated by a black dot have a ratio of 2:1
The Puzzle:
Try it on Sven's Sudokupad
Solution code: The second to last complements to appear - in numerical order from least to greatest. 4 digits (For example: 2664)
Solved by Reisen, amirschw, mihel111, ficko, micjo, rocky, OlafLemme, lsw770770, stenik, kublai, macronate, arteful, emoney1374, HumanBirdsong, pmatos, Counterfeitly, Nylimb, pmays123, M8tyw31, croo377, ... busby, jkuo7, zeniko, Dermerlin, starfall, Ftown778, cegie, samuella, JoroP, OJPS, plinke, 3ColorTheorem, Yoica, Exigus, cvil, Rjw78, Yudhishthir, scushuaishuai, Hrothan, Fool on Hill, Chuck
Comments
Last changed today, 13:18today, 05:00 by Decapod
I feel like this requires a deeper understanding of modular arithmetic than I possess.
Reply: That one box will need that - but nothing more. The key concept is to think about what is the remainder the digits when divided by three. {1, 4, 7} all have a remainder of 1. {2, 5, 8} all have a remainder of 2, and {3, 6, 9} all have a remainder of 0. If you consider what happens when you add combinations of these in light of their remainders, and what the remainder NEEDS to be, I hope you will discover what you need to step past that box. If you want a more specific hint, feel free to ask in a comment, or if your on discord hit me up there.
today, 01:37 by Freegerator
Fun puzzle, thank you!
yesterday, 21:11 by blackjackfitz
Huzzah!
yesterday, 20:22 by Franjo
Thank you very much for creating and sharing this nice and approachable math puzzle.
yesterday, 17:42 by wilsig
Fantastic puzzle!!
yesterday, 17:06 by pmays123
Very fun. Thanks!
yesterday, 17:03 by Nylimb
The interactions between the constraints were quite fun. Thanks.