The Archer's return
(Published on 18. April 2026, 00:45 by Killer Joe)
Hello.
Normal sudoku rules apply.
Digits are grouped into modular sets:
1 mod 3 → {1, 4, 7}
2 mod 3 → {2, 5, 8}
0 mod 3 → {3, 6, 9}
Cells with the same relative box positions must come from the same modular set. For example, if the first cell of box 1 contained a 5, every first cell of each box must contain digits from {2, 5, 8}.
Digits on an arrow sum to the digit in the attached circle.
Have fun.
Solution code: See completion message
Comments
on 22. April 2026, 15:10 by MEOW
took me 70 min to solve but very fun
on 21. April 2026, 18:37 by Anthony
Took me a bit to spot the break-in, but once I saw it the entire puzzle just completely fell apart.
on 19. April 2026, 21:48 by sparkymanu
Once you understand the implication of the modular relative position, it's very straight forward with basic sudoku tools so I think 1* is definetly more fitting here
on 19. April 2026, 07:53 by JVA
This puzzle has a 2* break-in and a very straightforward resolution after that, but that's still a 2*
on 18. April 2026, 18:32 by MikeyJoe
Agree with 2*. I am relatively new to variant Sudoku and it took me a few times looking at it to see the break in, but very easy afterwards.
on 18. April 2026, 15:41 by anothermember
I think 2* maybe. Just because the shading pattern is not obvious on the break-in unless you're familiar with various things (and then it's easy).
on 18. April 2026, 15:39 by macintux
Very easy once you figure out the break-in. That, however, takes some thinking.
Wonderful puzzle, thanks.
on 18. April 2026, 12:15 by Jasperrr
Very nice and actually a very easy 1*.
Another amazing glitch in the logic masters voting behaviour.
on 18. April 2026, 10:02 by jordanza
Interesting concept!
on 18. April 2026, 05:41 by ShaftESR
Very cool!
on 18. April 2026, 04:42 by Fisherman
Better than any TV show.
