Logic Masters Deutschland e.V.

Trichroma Paintomino #3

(Published on 12. March 2026, 20:36 by MaizeGator)

The third puzzle in the Trichroma Paintomino series continues to build upon the ideas introduced in #1 and #2. The “intended” difficulty is 3*, but you may find it easier, particularly if you’ve been getting familiar with the ruleset.

RULES:
  • Divide each bold-outlined region into three differently-sized sub-groups of cells. Then, assign one of three colors to each group so that each region contains exactly one group of each color.

  • A digit in a cell indicates the size of that cell’s group.

  • Sub-groups that border one another through a bold region boundary may not be the same color OR the same shape (counting rotations and reflections as the same). For example, two touching S-tetrominos in different configurations is not allowed, but an S-tetromino may touch a T-tetromino.

  • When the colors of the sub-groups for each region are placed in order from largest to smallest, any pair of bordering regions must have a different order.

A complete ruleset demonstration is available here

Solve the Example in Penpa

Solution code: The sizes of each cell’s sub-group row 5, left-to-right


Solved by Christounet, Piatato, tryote, sehringdipity, Chaossudokusplease, Calesch, Jesper, elmers, Franjo, puzzler05, zuzanina, Agent, Mr_tn, JustinTucker, josh_johnson, QuiltyAsCharged, PrimeWeasel, ... mellowrobinson, kyuquu, GaviGuy, MazzleFlush, mortaxic, cowabunghole, dogfarts, johnyzzh, Felis_Timon, misko, SFP, chenlu, webato, h5663454, Kpn, JennaStella, sfushidahardy, yttrio, Mark Sweep
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Comments

on 15. March 2026, 15:24 by QuiltyAsCharged
This ruleset works quite nicely. A brilliant invention!

on 13. March 2026, 19:05 by Agent
Neat!

on 13. March 2026, 13:23 by Franjo
Maybe you‘d better chosen another row for the solution code as the last (nice!) deduction didn’t use row 5? Anyway, thank you very much for creating and sharing another beautiful puzzle of this new genre.

on 12. March 2026, 22:00 by Piatato
Fun one again, thanks!

Difficulty:2
Rating:98 %
Solved:42 times
Observed:1 times
ID:000RV7

Enter solution

Solution code:

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