Logic Masters Deutschland e.V.

Erica 37 (German Quadruples Edition)

(Published on 10. March 2026, 15:00 by SennyK)

Erica 37 (German Quadruples Edition)

Today we have Erica created for Scojo's prompt with Quadruples and Duality clues :-)
I hope you will enjoy and I would be really grateful for all the comments and ratings.

Normal sudoku rules apply.

German Quadruples: Within the four cells surrounding a circle, orthogonally adjacent digits have a difference of at least 5, and a digit from a circle must appear at least once.

Kropki dots: Digits in cells joined by a white dot are consecutive. Not all dots are necessarily given.

SudokuPad Link

German Quadruples Explanation:

It is just a standard Quadruple (with repeats allowed) with a German whisper line around it.

If you liked this puzzle, I recommend trying out my other puzzles :-)

Solution code: First (1st) column of the grid from top to bottom.

Last changed on on 13. September 2026, 15:33

Solved by Ambrose, Piff, AlSina, ___, ole-1995a, TeamSchmidt, SKORP17, lmg131, brimmy, HeyItsErin, Exigus, SirWoezel, sfield, Flinty, ChinStrap, MathGuy_12, TheCutmaster, lina_hyena, Bjd, Silentdodo, ... Gcach, paranoid, Harold, WvdWest, ryugane, Ye Nay Myo Han, quinnikins, Chipmunk, thintheboxking, widjo, paintspotinfez, Ste1729, SimiC, me and the paws, lulu614, fina0110, Llamaths, SPOU1, Luaryo
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Comments

on 11. March 2026, 11:12 by Snookerfan
Amazing puzzle, loved it, thanks!

on 11. March 2026, 05:55 by ZigZagWonderer
I loved solving this puzzle. Really enjoyable, Thank you!

on 10. March 2026, 23:40 by sfield
Love this series. The only reason I tried a 3*. It was very challenging for me, but I got it.

on 10. March 2026, 22:45 by HeyItsErin
Probably my favorite Erica puzzle yet! I love seeing new constraints like this because I have to figure out new logic instead of going on auto pilot with what I already know. I would greatly enjoy doing another puzzle with this constraint.

on 10. March 2026, 22:29 by Donald X.
Cool puzzle.

Difficulty:3
Rating:92 %
Solved:82 times
Observed:4 times
ID:000RU0

Variant combination Online solving tool

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Solution code:

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