Dutch Flat Mates: The Greatest Mate
(Published on 18. February 2026, 07:00 by Prof.Dori)
Dutch Flat Mates: The Greatest Mate
It is a pleasure to make another puzzle for this series which first was initiated by Flinty. You can see the previous puzzle of the series on the following link Dutch Flat Mates: Three is a Crowd
Rules:
Normal sudoku rules apply.
On each line, there is exactly one cell whose value is greater than the sum of any other two cells on that line.
Every 5 in the grid must have a '1' directly above it or a '9' directly below it. It may have both, but it doesn't need both.
Click here to start the puzzle
Solution code: Row 8.
Comments
on 6. April 2026, 13:50 by kasperd
I love how you managed to get a unique solution with such a symmetric grid and rules that at a first glance look like they couldn't possibly break the symmetry.
on 18. March 2026, 23:03 by Qodec
Some very nice deductions in here. Thanks!
on 4. March 2026, 13:04 by Djirt
Спасибо, замечательная симметрия!
on 20. February 2026, 19:41 by blackjackfitz
Huzzah!
on 19. February 2026, 00:25 by psams
Interesting how much work was done by the 5 adjacent to 1 or 9 rule.
on 18. February 2026, 23:22 by Exigus
Very well constructed, thanks!
on 18. February 2026, 17:20 by Snookerfan
Incredibly good puzzle! Symmetrical and great fun, thanks!
on 18. February 2026, 14:17 by Fool on Hill
Cool puzzle - really interesting symmetry break
on 18. February 2026, 09:50 by antiknight
Great puzzle with a lovely break-in as well! It’s nice that it’s symmetrical too.
on 18. February 2026, 09:16 by Flinty
Wonderful stuff. Great use of symmetry. Thank you for setting.
on 18. February 2026, 09:16 by marcmees
Fantastic construction. Thanks
