Logic Masters Deutschland e.V.

quadcopter

(Published on 28. January 2026, 09:50 by arctan)

this puzzle appeared on 1/29/2026 on cracking the cryptic.

normal sudoku rules apply.

digits may not repeat along either diagonal.

digits along an arrow sum up to the digit in the arrow's circle.

if two digits are adjacent on a black line, then one digit is double the other.

if two digits are adjacent on a magenta line, then they are consecutive.

the grid is covered in fog; placing correct digits will clear the fog in that cell, and may also clear fog in other cells. no guessing is necessary to solve the puzzle.

play online (sudokupad)

cracking the cryptic solve

Solution code: row five, left to right

Last changed on yesterday, 19:02

Solved by godgamer2, chippers, Krisonium, jalebc, Ragna, Qodec, Gribba Bibba, jwsinclair, superkinkel, jseng, Uhu, SKORP17, n87, thionyl, Snookerfan, bansalsaab, Bionic Cheese, pshubes, Josh_Tuba, Aswen, fsw, ... Khatru, Klook, Centroid41, damo_89, Jasperrr, alta1r, DedaKosta, SirRookie, AKernel, Diddlmus, madhupt, LuridGraph, MaxSmartable, MikeMeech, Illuminated, EFlatMinor, Morisenseiisgod, fredchen
Full list

Comments

today, 03:00 by MikeMeech
Astonishing break in, and a few more interesting deductions to get it to come together!

yesterday, 19:02 by arctan
added link to ctc solve

yesterday, 09:17 by QuiltyAsCharged
Such lovely logic, bravo!

Last changed yesterday, 08:51

on 29. January 2026, 17:56 by Snookerfan
Very impressive puzzle! The break-in made sense to me when I discovered it, but I am still not 100% sure I have proven it to be right, although it did solve the puzzle. Thanks
___
thanks for the solve and the comment! posting a hidden comment with my thoughts on the break-in, and hopefully that cements your proof

Later yesterday while whatching tv (snooker actually :)), I kept thinking about it and found my proof and it was exactly what you intended. Sometimes I have to think a bit simpler. Great break-in!

on 28. January 2026, 17:37 by jwsinclair
Enjoyed this a lot :)

Difficulty:4
Rating:90 %
Solved:61 times
Observed:0 times
ID:000R6A

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Solution code:

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