Logic Masters Deutschland e.V.

Day 22: Yin-Yan

(Published on 22. December 2025, 06:00 by SharpFox)

SudokuPad
Rules:
  • Normal 4×4 Sudoku rules.
  • Yin-Yan: Shade some cells such that both the shaded and the unshaded cells are orthogonally connected and no 2×2 square is either fully shaded or entirely unshaded.
  • Red lines mark borders of differently shaded cells. Red crosses give the number of cells with the same shading among the (up to) 8 surrounding cells including itself.
  • Orthogonally adjacent cells of the same shading have different parity i.e. one digit is odd and one even.
  • Tiny tip: In this puzzle yin and yan are symmetrical i.e. it doesn't change anything if you change the shaded and unshaded cells.
Good Luck!

Solution code: Row 1 (4 digits):

Last changed on -

Solved by maniacaljackal, EFlatMinor, Lissa41585, Donatello_86 , Dee_Code, tiuhto, Dermerlin, superkinkel, xrrx, pepe74287, rcg, 3ColorTheorem, kehan628, Fizz, marcmees, walid_tun, patolucatis, Gizmo, ... ethteck, stafen, geronimo92, Raistlen, pzwack, BlackApolloX, mmmead, Saltman, Saskia11, Terrapin, Kekes, Chilimy, Devil, dalyons, EL Buderino, Ginge, LGeuerHonig, hirassy, killmymatrix
Full list

Comments

on 17. March 2026, 03:01 by Ginge
I find it interesting that if you changed the Red Crosses rule to say “Excluding itself” you still have a solvable puzzle (with a different solution, of course)

on 11. March 2026, 10:07 by EL Buderino
I really do not unterstand this one.
Even after having found the solution. ????

Last changed on 25. December 2025, 04:52

on 25. December 2025, 04:52 by FireTruckFuel
This puzzle seemed somewhat daunting given the rules so I read them through twice. Finished in only 1:13. I think my trepidation says more about my familiarity with Yin-Yan than it does about the puzzle itself. My favorite 4x4 of the series!

on 24. December 2025, 18:01 by tstaffor
The parity rule is very interesting for a shading puzzle.

on 22. December 2025, 19:19 by Fisherman
Happy holidays to all.

Difficulty:1
Rating:83 %
Solved:105 times
Observed:2 times
ID:000QNM

Enter solution

Solution code:

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