Entropic Alternation
(Published on 7. November 2025, 17:12 by Tinnifer)
I'm back with a new puzzle after a pretty long break. I really hope people enjoy this one, it took a lot of tweaking to get the logic to work the way I wanted. Feedback welcome as always!
Estimated difficulty: ★★★
- Normal sudoku rules apply: place the digits 1-9 once each in every row, column and 3x3 box.
- Entropic parity lines: every 3 adjacent digits on a red/peach line must contain one low (1,2,3), one middle (4,5,6), and one high (7,8,9) digit. Additionally, every 2 adjacent digits on these lines have different parity, i.e. one is even and one is odd.
- Little killers: digits on a marked diagonal sum to the clue given outside the grid.
- X/V: Digits separated by an X sum to 10. Not all such clues are necessarily given.
Play!
Solution code: Column 5, digits from top to bottom.
Solved by jalebc, TripleABattery, SKORP17, ymhsbmbesitwf, gxorgx, DiMono, Snookerfan, strangelyinsane, dtoto, benisjammin
Comments
Last changed on 8. November 2025, 01:42
on 8. November 2025, 01:16 by ymhsbmbesitwf
imo at least 4, unless it absolutely cracks with bifurcation. i didn't try that.
the logical deductions i found were satisfying, i really enjoyed the puzzle and even after stumbling didn't mind spending extra time starting over
---
Thanks a lot for your comment! Yes I was quite happy with this puzzle's logic as well, and I'm glad you enjoyed!
-T
