Logic Masters Deutschland e.V.

Holy Moly (Chaconopia)

(Published on 6. November 2025, 14:01 by Mad-Tyas)

This is my 18th Chaconopia puzzle overall and the third one featuring the special role “Bishop.” It marks the climax and conclusion of this first series of puzzles with the new role. There will definitely be more puzzles with the “Bishop,” but first I plan to introduce a new special role. Stay tuned!

Sudoku on:
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Rules:

1. Chaos Construction: The grid has to be devided into nine regions of orthogonally connected cells. Each row, column and region has to contain the digits 1-9 once each.

2. Roles: If certain conditions are met, cells can take roles that increase their value. The value of a cell with no role is it's digit. Role values and conditions are described below.

2.1 Role conditions and values (X = Digit in a cell)

2.1.1 Basic roles:
- Farmer (Value = 2X): To become a Farmer, a cell needs at least X cells including itself of its own region in the 3x3 area centered on the cell.
- Merchant (Value = 3X): To become a Merchant, there has to be at least one foreign region that occupies at least X orthogonally and/or diagonally touching cells of the considered cell.
- Diplomat (Value = 4X): To become a Diplomat, a cell has to be orthogonally and/or diagonally touched by at least X different other regions.

2.1.2 Special role:
- Bishop (Value = 5X): To become a Bishop, a cell needs to see at least X cells of its own region including itself in diagonal directions. Cells from other regions block the view.

2.2 Role assignation: Basic roles are automatically taken if their condition is met. If more than one condition is met, a cell takes the role with the highest value.
The Special role "Bishop" may appear only once per region and can either be taken by a cell with no role or replace the Basic role of a cell. Of all cells in a region which meet the condition to become a Bishop, the Bishop role is taken by the cell that can gain the highest increase in value by becoming the Bishop. In case of a tie, all cells involved could be the Bishop and it has to be determined by the solver which of the cells is the Bishop.

3. Clues:
- Values along an arrow must sum to the value in the attached circle.
- In cages marked with a dashed line the values have to add up to the total given in the top-left corner of a cage.

Have fun solving!


Example: This is an 5x5 example picture to show how roles are assigned to cells. White circles mark the bishop cell in a region. In Region A, I only marked the cells that meet the Bishop condition (grey circles) and you can try to determine the Bishop as a little exercise. Basic roles are not marked:
- Regions B and E: The cell with 1 is the only cell that meet the Bishop condition and therefore is the Bishop.
- Region C and D: The cells with 1, 2 and 3 all meet the Bishop condition. In Region C the cell with 2 is the Bishop as it can increase it's value by 4 (from 6 to 10) compared to it's Basic role (Merchant). The cell with the 3 has the Basic role Diplomat with a value of 12 and could increase it's value only by 3 (from 12 two 15). In Region D it's the other way around.
- Region A: The cells with 1 and 2 meet the Bishop condition. Try to determine which cell is the Bishop.

Solution code: The 9 digits from row 5 (top-to-bottom) separated by (+) for borders between regions


Solved by War, han233ing, Isael, sehringdipity, Gnosis66
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Comments

on 13. November 2025, 19:08 by Gnosis66
This was a puzzle with stunning logic that the solver had to deduce by going down lots of different avenues.

on 7. November 2025, 05:55 by War
I stayed up late because I saw this posted. Absolutely phenomenal break in logic. I think Min-Max arrows pairs exceptionally well with Chaconopeia, and made the bishop shine in this puzzle. I see you clarified that bishops are allowed to tie in this puzzle, I don't remember if that was allowed in the previous few, but it is a necessary rule here. Thanks for this masterpiece, I didn't appreciate the bishop until now.

Difficulty:5
Rating:N/A
Solved:5 times
Observed:0 times
ID:000Q04

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