diploptic triptych
(Published on 20. October 2025, 20:20 by aqjhs)
This one is heavily inspired by ChinStrap's Cross-eyed.
- Place a digit from 1-9 into every cell such that digits do not repeat in a row, column or 3x3 box. There are nine 3x3 boxes that overlap at the dotted lines.
- Parity Mirror: Each cell has the same parity as the cell reflected across the marked diagonal (e.g. if r2c6 is even, r6c2 is also even).
- A clue outside the grid is the sum of the first X cells in the corresponding row/column, where X is the digit in the cell nearest to the clue.
See also:
Solution code: Column 2, top to bottom.
Last changed on -
Solved by lmdemasi, bansalsaab, SKORP17, tuturitu, Calvinball, Bankey, Megalobrainiac, waffles_the_dog, Dentones, Piff, dodo, Exigus, SPring, Isael, dipiz, AAAAAAAAAAAAAAAAAAA, abed hawila, paranoid, Andrewsarchus
Comments
on 22. October 2025, 15:34 by Exigus
Found the midgame tricky after the first few digits, had two possible worlds that were hard to distinguish. Very nice puzzle, thanks!
on 21. October 2025, 10:21 by waffles_the_dog
Really fun, I got stuck for a bit just at the end when I forgot one of the earliest deductions, and then had a moment of "I broke it" because I forgot the main parity mirror rule :D
Great fun, thanks for setting it :D
on 21. October 2025, 07:43 by Bankey
First time I attempted a squish puzzle. Great fun. Thanks, @ aqjhs :).
