Breaking Even
(Published today, 02:22 by Killer Joe)
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Hello.
Normal Sudoku rules apply.
Digits in a cage sum to the small clue given in its top-left corner without repeating digits.
Within each 3×3 box, all digits belonging to the same cage segment (the part of the cage inside that box) must have the same parity — either all odd or all even.
A cage may change parity when it crosses a 3×3 box boundary, but this is not required.
Have fun.
Solution code: row 9, first 6 digits
Last changed on today, 06:40
Solved by mellowrobinson, mariban, zonny, starfall, by81996672, Silentdodo, gxorgx, redgecko, damyan_rm, randall, jalebc, DanishDynamite, EmX68, Megalobrainiac, Ol-Jay, Sudokode, Yoica, keenbowl, haaksema, samuella, brimmy, Killer-Ly , luoji, Alce, Platinum, terrible_casserole, zuzanina, SKORP17
Comments
today, 06:40 by Killer Joe
Updated ruleset.
today, 04:11 by starfall
Good puzzle! I had done it supposing that the digits in a cage must be different. I wonder if it is necessary
