Logic Masters Deutschland e.V.

The amicable prodigy

(Published on 5. March 2025, 05:40 by NicoD)

The amicable prodigy by Nicolas Duhail.

This is part 2 of my 6x6 friendly cells trilogy.
Part 1: Moody friendship
Part 3: Pygmy Python

Rules
Normal sudoku rules apply.
In this puzzle, half of the cells are "friendly".
A cell is "friendly" if it contains its row, column, or box number.
Cells separated by a knight's move cannot contain the same digit.
In the finished grid, each 2x2 square of cells has to contain at least one low digit (1/2/3) and one high digit (4/5/6) [Global entropy].
Digits separated by an X sum to 10, and they are ALL given.

Optional rule to make the puzzle easier:
Digits separated by a V sum to 5, and they are ALL given.

Play this puzzle on SudokuPad

Solution code: Row 2

Last changed on on 6. March 2025, 03:59

Solved by SincereEngineer, pms_headache, gdc, Snookerfan, SKORP17, zeniko, mego, faisalaak, Crusader175, annnz, -Tsigje-, benisjammin
Full list

Comments

on 6. March 2025, 03:59 by NicoD
Edit: added links to parts 1 and 3.

Last changed on 5. March 2025, 14:24

on 5. March 2025, 11:18 by Snookerfan
Very nice. I found some of the deductions a little bit a long chain, therefore hard to spot. The global entropy did some heavy lifting, which I liked a lot. In the end everything came together really well. Thank you
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ND: Thanks, glad you enjoyed.

Difficulty:3
Rating:N/A
Solved:12 times
Observed:6 times
ID:000M9E

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Solution code:

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