Logic Masters Deutschland e.V.

Bedazzled

(Published on 7. May 2021, 18:54 by GarlicBredFries)

Normal sudoku rules apply.
A black square signifies that the two squares opposite (diagonally) have a ratio of 1 to an integer.
A black circle signifies that the two ratios are the same (still 1 to an integer).
A white square signifies that the digits opposite do not have a ratio of 1 to an integer.
Digits along an arrow sum to the number in the circle.
Link (f-puzzles): https://f-puzzles.com/?id=yzwbklsa

Solution code: Column 8 then 9 top to bottom

Last changed on on 25. May 2021, 22:05

Solved by JohnDoeJersey, Tilberg, Florian Wortmann, NikolaZ, ogi.djukovic, geronimo92, Vebby, juventino188, cfop, thinkingalaud, Cane_Puzzles, michaal94, Uhu, OGRussHood, zhergan
Full list

Comments

on 25. August 2021, 20:45 by uvo_mod
Labels angepasst.

on 25. May 2021, 22:05 by GarlicBredFries
Added line breaks

on 9. May 2021, 22:32 by GarlicBredFries
Clarified the rules a bit

Last changed on 9. May 2021, 09:29

on 9. May 2021, 09:19 by Tilberg
@Garlic: Yes, I understand, that's what I thought. Maybe you should clarify the ruleset then, because as it is now, it leads to two solutions and, by the way, destroys a lot of the beauty you put into the puzzle.

Because if we know that ratio has to be "1 to an integer" too, it's a very tough, but enjoyable puzzle with some pleasant surprises and an interesting solution path.

While, if any ratio around a black circle is allowed, as long as it's repeated, the solve loses its clarity, becomes quite tedious and "bifurcaty", and in the end, still allows for two possible solutions, which is a big let-down.

on 9. May 2021, 00:01 by Florian Wortmann
Interesting ruleset with some intricate logic that leads to an enjoyable solve.

Last changed on 8. May 2021, 23:58

on 8. May 2021, 23:56 by GarlicBredFries
@Tilberg when I meant the ratio is the same, I meant that it is still a ratio of one to an integer on both sides and the ratio across a circle are both the same (ex: you could have 1-2 and 4-8 or 3-9 and 2-6)

on 8. May 2021, 11:27 by Tilberg
@Skorpio: Es bedeutet, daß zwei Ziffern, die sich beiderseits eines weißen Quadrats befinden, NICHT in einem ganzzahligen Verhältnis stehen dürfen, sprich keine der beiden ist ein Teiler oder Vielfaches der anderen. 2-8 oder 3-6 wären nicht erlaubt, 5-7 oder 3-4 hingegen schon.

Last changed on 7. May 2021, 21:57

on 7. May 2021, 19:31 by SKORP17
dass mit den weissen square ist unverständlich, bitte ein Beispiel einfügen

Difficulty:4
Rating:91 %
Solved:15 times
Observed:4 times
ID:00067C

Puzzle variant Online solving tool

Enter solution

Solution code:

Login