Shifted XV-Sandwich
(Published on 8. May 2020, 22:00 by Rawcoder)
This is a „9x9“- Sudoku-Variation, where the rows are shifted alternately. This is a new Variation, best to my Knowledge. If somebody did a grid like this before, please let me know.
Rules:
Place the number 1 to 9 in the grid so that each row, column and marked 3x3 box contains each number exactly once. Additionally, the 9 cells that are shifted to the side contain the digits 1 to 9 exactly once as well.
Wherever two neighboring cells add up to 10, there is an X in the grid. Wherever two neighboring cells add up to 5, there is an V in the grid. All possible Vs and Xs are given, i.e. when there is no X or V, the neighboring cells do not add up to 10 or 5 respectivly.
Clues outside the grid indicate the sum that are sandwiched between the digits 1 to 9.
The puzzle should be quite easy and can be solved nicely.
Enjoy!
Solution code: Row 1 followed by row 2. (The digits from the two cells shifted to the side must be included. The solutioncode is 18 digits long)
Comments
on 27. August 2020, 14:02 by Rollo
Großartig! Ich hab's viermal anfangen müssen.
on 9. May 2020, 20:58 by Rawcoder
@Eloi.blok As Joe Average correctly said, it's a 9x9 grid with every other row shifted by one cell. So in total we still have 81 cells, but because of the shifted rows there simply can not be 9 3x3 blocks.
on 9. May 2020, 20:01 by Joe Average
There are no middle boxes in the classical sense.
It's a 9x9 grid, but every second row is removed by one cell.
on 9. May 2020, 18:40 by Eloi.blok
I don t understand where are the boxes of the middle, or there are not?
