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CrocoPuzzle Adventskalender 2011: Tag 8 (Römische Summen II)

(Published on 8. December 2011, 08:00 by berni)


This puzzle is part of the

CrocoPuzzle Adventskalender 2011


Instructions: Write one of the seven roman numerals into every cell: M, D, C, L, X, V and I. The separate the resulting roman numbers from left to right and from top to bottom as follows: Cut the largest part, that still is a regular roman number. Do the same with the remaining tail if there is any. (Example: In the first column is a C which is a regular roman number. CV again is a regular roman number, but CVD issn't. Therefore The number is separated below the V.) The numbers at the borders give the sum of the roman numbers in that row or column.

ExampleSolution

Definition of a regular roman number: A regular roman number is calculated subtracting the numbers of the following table from top to bottom and writing the according roman numerals from left to right. Always take the largest possible number in the table until you reach 0.

MCMDCDCXCLXLXIXVIVI
1000900500400100905040109541

Example: If you want to calculate the regular roman number which belongs to 3498 you will first subtract thrice 1000 and write MMM. That you subtract 400 and write CD. After that you can subtract 90 which results in XC than 5 which is V and at last thrice 1 which is III. Together you get MMMCDXCVIII.

Solution code: The roman numerals of the diagonal from top left to bottom right. In the example the code would be CXV.

Last changed on on 12. February 2013, 13:23

Solved by saskia-daniela, Luigi, deu, r45, BFaw, pokerke, MiR, ch1983, Statistica, audrey, uvo, ffricke, Mathi, hopppe, yusaku, rimodech, Antarez, moss, ManuH, Marian, Toastbrot, Dandelo, Jun, micke8, ... jirk, Babsi, RALehrer, Thomster, relzzup, marsigel, ildiko, sf2l, adam001, flooser, Ute2, jimrity, Joe Average, matter, tuace, pandiani42, Matt, pirx, jessica6, Carolin, Nothere, athin, EKBM, misko
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Comments

on 12. February 2013, 13:23 by berni
Stichwort hinzugefügt

Last changed on 9. December 2011, 17:27

on 9. December 2011, 17:26 by Rollo
Das war auch meine Zahl, eine schöne Falle!

on 9. December 2011, 16:50 by HaSe
jau, Turbobrett - ich sag kein Wort mehr

on 9. December 2011, 15:44 by CHalb
HaSe, genau das meinte ich ;-).

Last changed on 9. December 2011, 14:45

on 9. December 2011, 14:45 by berni
@Hartmut: Rechne nochmal genau nach. ;-)

on 9. December 2011, 14:13 by HaSe
naja, gelöst hab ich es ja (zumindest auf der Diagonalen wohl auch korrekt) - brauche weitere Details

on 9. December 2011, 14:05 by CHalb
Nicht nur an HaSe: Mir ging's ähnlich. Wie ich es auch betrachtete, ich geriet immer in Widersprüche. Und das lag nicht an den Rätselregeln sondern an römischen Zahlen, die ich nicht bedacht habe.

on 8. December 2011, 10:27 by berni
Englische Beschreibung hinzugefügt.

on 8. December 2011, 10:19 by saskia-daniela
weniger vielleicht, aber ohne schaff ich's noch nicht durch ;-)

on 8. December 2011, 08:44 by r45
Klasse Idee. Die Momente, in denen man Widersprüche erkennt, die keine sind, werden schon weniger. ;-)

Difficulty:2
Rating:78 %
Solved:115 times
Observed:5 times
ID:00017J

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